Simple Shell/Bash Program Syntax

Question

I have the following bash script:

#!/bin/bash
if [ ! -f numbers ]; then echo 0 > numbers; fi
count = 0
while [[$count != 100]]; do
count = `expr $count + 1`
done

When I run it in terminal on my Mac, I get the following output:

seq_file_gen.sh: line 3: count: command not found
seq_file_gen.sh: line 4: [[: command not found

Why am I getting these errors? This script was given to me by my teacher so I have no idea why I can't get this script to run. Any help would be greatly appreciated.

EDIT: This is the correct way to write this script (with spaces)

 #!/bin/bash
 if [ ! -f numbers ]; then echo 0 > numbers; fi
 count=0
 while [[ $count != 100 ]]; do
 count=`expr $count + 1`
 done

What is the reason for the down vote? It seems impossible to ask a basic question without getting down voted. — dhint4
– dhint4, Commented Feb 9, 2015 at 20:18
Do not use spaces around the equals: write count=0 and count=`expr $count + 1`. I didn't apply the downvote, but I suppose it may be because these are basic shell syntax issues that are determined from reading documentation. — lurker
– lurker, Commented Feb 9, 2015 at 20:24
also you still don't have space in 100]] and what's with the 'numbers' on line 2? Is this even a complete script? — guessimtoolate
– guessimtoolate, Commented Feb 9, 2015 at 20:25
I forgot to change it. It worked after I put the space back in. Thanks for the help. Will accept as best answer when I am able to. — dhint4
– dhint4, Commented Feb 9, 2015 at 20:26
You can always run your programs with shellcheck.net to get some fast checking with good explanations. — RedX
– RedX, Commented Feb 9, 2015 at 20:45

guessimtoolate · Accepted Answer · 2015-02-09 20:17:53Z

1

Add spaces before/after [[ and ]] like so:

while [[ $count != 100 ]]; do

answered Feb 9, 2015 at 20:17

guessimtoolate

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