java script not working while validating the fields in php

Question

i am validating 3 fields in html that they are empty or not .

the code is

<input type="file" id="uploadImage" name="image" />file1:
<input type="file" name="QRimage" id="File2" />file2:
<label for="name">Student information:</label>

<input  type="checkbox" name="person" id="person" >Yes

javascript:

   function validate()
       {
     var empt = document.forms["form1"]["image"].value; 
     var empt1 = document.forms["form1"]["QRimage"].value; 
     var empt2 = document.forms["form1"]["person"].value;  

     if (empt == "" && empt1 == "" && empt2 != "checked" )  
       {  
        alert("Please input a Value");  
       return false;  
       }

Problem: if those 3 fields are empty then its gives the alert message that ("please input a value") . but if checked the check box the allso its giving same message rather than going next page . where i am wrong ?

where you have applied the validate() ? provide complete form (HTML). — jogesh_pi
– jogesh_pi, Commented Feb 10, 2015 at 11:12
The value of empt2 will never be 'checked', you've to compare ][person].checked (which will be a boolean) instead of value. What has PHP to do with this question? — Teemu
– Teemu, Commented Feb 10, 2015 at 11:12

Jivings · Accepted Answer · 2015-02-10 11:12:54Z

3

You want to access the checked property (which is a boolean) of the checkbox, not the value:

var isChecked = document.forms["form1"]["person"].checked;  

if (empt == "" && empt1 == "" && !isChecked) {  
    alert("Please input a Value");  
    return false;  
}

answered Feb 10, 2015 at 11:12

Jivings

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1 Comment

Nayana Over a year ago

Sorry Jivings it was not working with "!isChecked" . i used empt2 == "" then its working . anyway thanks for helping

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