php recognizing string as array

Question

I have the following code

dd(gettype($default));
$test = substr($default,0,2);

gettype returns that the type of $default is string The following error happens on the second line:

substr() expects parameter 1 to be string, array given

How is this happening, and how can I solve it?

edit var_dump also returns a string as type

edit $default contains the following string: "1015"

edit complete code block

Form::macro('time', function ($name, $default) {
$hours = value(function () use ($default){
    echo gettype($default);
    $test = substr($default,0,2);
    $hours = ['' => $test];
    for ($hour = 0; $hour < 24; $hour++) {
        $hours[$hour] = $hour;
    }
    return $hours;
});

edit code where the macro is used

{{ Form::label('reservation_starthour', 'starthour') }}
{{ Form::time('starthour',$reservation->starthour) }}

Schema of the reservation table

Schema::create('reservations', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('group_id')->unsigned();
        $table->date('startdate');
        $table->date('enddate');
        $table->string('starthour');
        $table->string('endhour');
    });

@VeeeneX It's a built in Laravel function: var_dump and die, dd. If you dd($default) without the gettype what does it return? — Tim Lewis
– Tim Lewis, Commented Feb 11, 2015 at 20:47
Do some basic trouble shooting, Var Dump all variables to see what they're worth — Patrick
– Patrick, Commented Feb 11, 2015 at 20:47
dd(gettype($default));var_dump($default);$test = substr($default,0,2); If var_dump will be array then it means that the problem is in dd() — VeeeneX
– VeeeneX, Commented Feb 11, 2015 at 20:48
@VeeeneX The problem isn't in dd(). That function doesn't modify anything. — Tim Lewis
– Tim Lewis, Commented Feb 11, 2015 at 20:49
@TimLewis This is becoming a strange question, what do you think that can be the problem? — VeeeneX
– VeeeneX, Commented Feb 11, 2015 at 20:50

AbraCadaver · Accepted Answer · 2015-02-11 20:49:28Z

1

gettype returns the type of the variable as a string result and that result might be "array", but it's still a string. So the dd / var_dump shows it as a string. Try:

echo gettype($default);

answered Feb 11, 2015 at 20:49

AbraCadaver

79.2k7 gold badges75 silver badges91 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

JorenV Over a year ago

that also returns the type as string

JorenV · Accepted Answer · 2015-02-12 11:17:21Z

I was able to find a workaround, but not an explanation why the variable changed types.

Form::macro('time', function ($name, $default) {
$hours = ['' => substr(strval((int)$default),0,2)];
for ($hour = 0; $hour < 24; $hour++) {
    $hours[$hour] = $hour;
}

$minutes = ['' => substr(strval((int)$default),2)];
for ($minute = 0; $minute < 60; $minute += 15) {
    $minutes[$minute] = $minute;
}
return
    Form::select($name . '[hours]', $hours) .
    Form::select($name . '[minutes]', $minutes);
});

I cast the string/array to an int, get the string value, and then I could get the substring value.

I will leave this question open so someone can maybe shed some light on why the types changed.

additional information

Every function requiring a string as input, stated that $default was an array. Every function requiring an array as input, stated that $default was a string.

Collectives™ on Stack Overflow

php recognizing string as array

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related