How can I get a string(Mix of digit and char) up to last digit using regex in python?

Question

I have strings like:

" 5473 & 4835 how to find the index"

" 5473 how to find the index"

" 5473 & A-121-2 how to find the index"

" A-121-2 how to find the index"

How can I extract the string up to last digit using regex.

For example, the result I want in above is like this:

" 5473 & 4835"

" 5473"

" 5473 & A-121-2"

" A-121-2"

Avinash Raj · Accepted Answer · 2015-02-12 11:32:54Z

2

Use greediness of *

^.*\d

^ asserts that we are at the start of a line.
.* will greedily matches all the characters upto the last
\d and then it backtracks in-order to find a digit character.

Example:

>>> re.search(r'^.*\d', " 5473 & 4835 how to find the index").group()
' 5473 & 4835'
>>> re.search(r'^.*\d', 'A-121-2 how to find the index').group()
'A-121-2'

DEMO

edited Feb 12, 2015 at 11:32

answered Feb 12, 2015 at 11:27

Avinash Raj

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3 Comments

Rahul Jain Over a year ago

Can you please tell how does this work? I am trying to learn regex

Rahul Jain Over a year ago

Thanks a lot. It worked. One more question: What if I have something like "No.- 12345 asbf" and I only need to get the result as "12345".

Avinash Raj Over a year ago

re.findall(r'\d+', string) .

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