Find Multiple Flagged String within String Python

Question

I have multiple flagged strings:

FLGSTdata1FLGEN
FLGSTdata2FLGEN
...

where FLGST is start flag and FLGEN is end flag.

I combine those strings and add some garbage data, so it looks like this:

garbagegarbageFLGSTdata1FLGENFLGSTdata2FLGENgarbagegarbageFLGSTdata3FLGEN...

I need to get each of flagged strings from the combined strings.

Here is what I've done using re:

>>> pattern = r'5354([A-Za-z0-9_]*)454E' #FLGST = 5354 and FLGEN = 454E
>>> data = re.findall(pattern,stringWithGarbage)
>>> print data[0]
data1FLGENFLGSTdata2FLGENgarbagegarbageFLGSTdata3

It returns all data except the FLGST of data1 and FLGEN of data last.

So, how do you get each of flagged string from stringWithGarbage?

The appropriate return would be:

[data1, data2, data3, ...]

possible duplicate of Python - Use a Regex to Filter Data

ivan_pozdeev
– ivan_pozdeev

2015-02-13 06:54:51 +00:00
Commented Feb 13, 2015 at 6:54 — ivan_pozdeev
– ivan_pozdeev, Commented Feb 13, 2015 at 6:54

Sede · Accepted Answer · 2015-02-13 07:19:13Z

1

using positive look behind and positive look ahead

strg = "garbagegarbageFLGSTdata1FLGENFLGSTdata2FLGENgarbagegarbageFLGSTdata3FLGEN"
pattern = re.compile(r'(?<=FLGST)(\S*?)(?=FLGEN)')
re.findall(pattern, strg)

Output

['data1', 'data2', 'data3']

answered Feb 13, 2015 at 7:19

Sede

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