value from 'HTML' form to 'PHP' file is not going to php file

Question

My task is i want to create form for search field. want to transfer the value from search to required php file which is 'result.php'. But I am getting bug that I am unable to solve this. please anyone help me. I am new to php..

HTML CODING :

 <form action="result.php" method="POST">
    <input type="search" name="query" size="10" id="searchfield" title="searchfield" />
    <input type="submit" name="Search" value="" alt="Search" id="searchbutton" title="Search" />
    </form>

PHP CODE :

//result.php

@session_start();
include 'connections.php';
//echo "hai"; // I debug this code with the help of echo statements. and  successfully printing hai

if (isset($_POST['query']) && $_POST['query'] != ""){// unable to enter in `if` condition 
$query = $_POST['query'];
$min_length = 1;
if(strlen($query) >= $min_length)
{
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
............`

value that entered in search field is not going from 'HTML' form to 'PHP' file to perform required operations please anyone help me to solve this bug..

In your comments where you are echo'ing out the $query, you are assigning incorrectly, you have $query = var_dump($_POST['$query']); but further down you assign it correctly using $query = $_POST['query']; — Endacy
– Endacy, Commented Feb 13, 2015 at 11:45
with the help of var_dump() i am just checking what value is I am getting... and its just debugging.. I did debugging by echoing the simple statements — subramanyemm
– subramanyemm, Commented Feb 13, 2015 at 11:49
you might want to change how your using mysql - code.tutsplus.com/tutorials/… — Oliver Bayes-Shelton
– Oliver Bayes-Shelton, Commented Feb 13, 2015 at 11:49
to check the value, just do : $query = $_POST['query']; echo $query; — Endacy
– Endacy, Commented Feb 13, 2015 at 11:52

Nejc Rodošek · Accepted Answer · 2015-02-13 13:33:36Z

1

If the values is printed with var_dump($_POST['query']);then it's actually sent by form. And why are you testing twice for lenght of it. Try testing if value is set in file where you got form. Test it with jquery. Then in result.php just check if value is posted. And what are you trying to do with value in result.php?

Try

var_dump($_POST['query']);
if (isset($_POST['query'])){// unable to enter in `if` condition due to NULL value.
$query = $_POST['query'];
$min_length = 1;
if(strlen($query) >= $min_length)
{
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
}
}else
{
echo 'novalues';
}

EDIT

You can try sending value with ajax. Add below code in script tag in your file with form and thats it.

    $("#searchbutton").click(function(){ 
    var value = $("#searchbutton").val(); 
    $.ajax({
    url: "result.php",
    type:"POST",
    data: value, 
    success: function(result){
     $("#div1").html(result); 
    }
    }); 
   });

edited Feb 13, 2015 at 13:33

answered Feb 13, 2015 at 11:51

Nejc Rodošek

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7 Comments

arnoudhgz Over a year ago

var_dump($_POST['$query']); in your explaination, lose the $ for query ;)

subramanyemm Over a year ago

we are developing simple library website. we have books in our database. developing search operation.. for that...

subramanyemm Over a year ago

not worked... same as before I am getting NULL with var_dump($_POST['$query']);

Nejc Rodošek Over a year ago

Hmm. Try removing @ before session, so you will see if any errors there. Then try putting type of input to text instead of search (html5).

subramanyemm Over a year ago

I am sorry to say, It doesn't work for me @NejcRodošek

|

Branimir Đurek · Accepted Answer · 2015-02-13 13:57:11Z

1

Try to change type of your input like this

<input type="text" name="query" size="10" id="searchfield" title="searchfield" />

just to be sure it doesn't cause your problem :)

answered Feb 13, 2015 at 13:57

Branimir Đurek

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4 Comments

subramanyemm Over a year ago

No use... @Branimir Durek

Branimir Đurek Over a year ago

well your code looks fine... press f12 and open network tab. Then submit your form and check your request POST data to be sure that your form sends "query" value. If it works, then try to comment everything and then echo $_POST["query"] just to be sure that rest of your code doesn't cause the problem...

subramanyemm Over a year ago

nothing worked for me. I don not know why.. even I checked with ajax and javascript. value from 'html' form to php file is not getting.......

Branimir Đurek Over a year ago

are you sure you don't have duplicated project?? So you edit one, but you test functionality on other...

subramanyemm · Accepted Answer · 2015-02-20 10:45:52Z

0

finally I resolved my problem.. problem occurred due to "access permissions" I rewrite the access permissions.. now it is working thank to everyone

answered Feb 20, 2015 at 10:45

subramanyemm

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