C++ - Function pointer with arbitrary number of args

Question

I'm trying to make a CPP function that takes a function pointer and an arbitrary number of arguments, adds some coordinates, then calls the function pointer as such:

int func_api(void(*fun)(int, int, ...args), ...args) {
    fun(this.x, this.y, args);
}

so I can use it as such:

int func(int x, int y, int param1, int param2) {
    something;
}

int foo () {
    func_api(p1, p2);
}

Is there a way to do this?

You could use variadic templates. You might be interested in libffi — Basile Starynkevitch
– Basile Starynkevitch, Commented Feb 13, 2015 at 23:26

Columbo · Accepted Answer · 2015-02-13 23:26:10Z

2

Use a variadic template

template <typename Func, typename ... Args>
int func_api(Func fun, Args&&... args)
{
 fun(this->x, this->y, std::forward<Args>(args)...);
}

You can now call it like this:

func_api(func, p1, p2);

edited Feb 13, 2015 at 23:26

Columbo

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answered Feb 13, 2015 at 23:25

Pradhan

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