How to put viewbag value as a variable in javascript/ jquery?

Question

I try to put two variable in JQuery which came from viewbags :

        $("#btnAdd").click(function () {
        var url = dev + "/Legacy/PutContentInThematic";
        var GroupingId = $("#GroupingId_Dialog").val();            
        var Title = $("#Title_Dialog").val();
        var Synopsis = $("#Description_Dialog").val();
        var image = $("#Image_Dialog").val();
        var ThematicId = @ViewBag.thematicid //Here i can't put ';'
        var ThematicName =  @ViewBag.Name

        $.ajax({
            url: url,
            cache: false,
            type: 'POST',
            data: {
                GroupingId: GroupingId,
                ThematicId: ThematicId,
                Title: Title,
                Synopsis: Synopsis,
                Image: image,
                ThematicName: ThematicName
            }
        });
    });

The problem concerns the two last variables "ThematicId" And "ThematicName", it is impossible to put ';' at the end, so the second variable ThematicName don't work.

I try to put this variable out of the function, but i doesn't work anymore. Have you and idea to fix it or an other solution for this Ajax call ?

Ehsan Sajjad · Accepted Answer · 2015-02-16 11:51:18Z

10

You need to write it this way:

var ThematicId = parseInt('@ViewBag.thematicid');
var ThematicName =  '@ViewBag.Name';

edited Feb 16, 2015 at 11:51

answered Feb 16, 2015 at 11:11

Ehsan Sajjad

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5 Comments

timothyclifford Over a year ago

This only works if both ViewBag values are strings, what if thematicid is an integer?

Ehsan Sajjad Over a year ago

@Ashley posted how to do for int

Oluwafemi Over a year ago

you can also check to see if the variable contains only integer... pietschsoft.com/post/2008/01/14/…

Ehsan Sajjad Over a year ago

@Julien698 welcome, parseInt() will work, if the value is int otherwise it will not, so consider @Olluwafemi commented link as well which suggests

Julien698 Over a year ago

You're right, but in my case i'm lucky because Thematicid is an int.

Ashley Medway · Accepted Answer · 2015-02-16 11:16:41Z

3

var ThematicId = @(ViewBag.thematicid); //For int
var ThematicName =  '@ViewBag.Name';   //For string

answered Feb 16, 2015 at 11:16

Ashley Medway

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6 Comments

Julien698 Over a year ago

For the first variable it don't work for me it says that ';' at the end is an error, so i use the solution with parseInt

Ashley Medway Over a year ago

@Julien698 Where does it say this is an error? The view should be valid with this syntax.

Julien698 Over a year ago

the error is on the ; at the end of the first variable

Ashley Medway Over a year ago

@Julien698 When you try and run the website what is the error message you are given?

Julien698 Over a year ago

The Website run without error, but is't juste in the page before to run. imageshack.com/a/img673/7188/A3nPwV.jpg

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