display php variables in bootstrap Navbar

Question

i want to display Usernames after login or signup in the Navbar using the function links () but the variable holding the username wont show, only displays "$acn";

 function links()
{
if(!isset($_SESSION['username']))
     {
         echo '         <div class="collapse navbar-collapse" id="signup">
            <!--<form class="navbar-form navbar-right" role="search">
              <div class="form-group">
                <input type="text" class="form-control" placeholder="Search">
              </div>
              <button type="submit" class="btn btn-default">Submit</button>
            </form>-->
          <ul class="nav navbar-nav navbar-right" id="signup">
            <li><a href="signup.php"><span class="glyphicon glyphicon-user"></span> Sign Up</a></li>
            <li><a href="index.php"><span class="glyphicon glyphicon-log-in"></span> Login</a></li>
          </ul>
        </div>';
         }
         else
         {
           $acn= $_SESSION['username'];
        echo   '<div class="collapse navbar-collapse" id="signup">
          <ul class="nav navbar-nav navbar-right" id="signup">
            <li><a href=\"account.php\"> $acn </a></li>
            <li><a href="logout.php"><span class="glyphicon glyphicon-log-out"></span> Log Out</a></li>
          </ul>
        </div>';
    }
}

and the function appears like this

<nav class="navbar navbar-inverse" role="navigation">
    <div class="container-fluid">
        <div class="navbar-header">
          <a class="navbar-brand" href="#">OOOO</a>
            <button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#signup">
                <span class="icon-bar"></span>
                <span class="icon-bar"></span>
                <span class="icon-bar"></span>
            </button>
        </div>
        <?php echo links(); ?>
    </div>
</nav>

How do i achieve this please, thanks.

thatidiotguy · Accepted Answer · 2015-02-17 16:59:59Z

1

In PHP, if you have a string wrapped in single quotes variables will not be parsed.

'$acn' is just a string with the value $acn. "$acn" will be parsed to be the value of the $acn variable.

Please also note that you are echoing the output of the links() function, but that function has no return value.

answered Feb 17, 2015 at 16:59

thatidiotguy

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Comments

William George · Accepted Answer · 2015-02-18 00:31:55Z

0

While your use of $acn would work fine in double quotesit does not behave in the same manor when contained inside single quotes.

If you wish to use single quotes you must concatenate the string:

  <li><a href=\"account.php\"> '.$acn.' </a></li>

Other things to note with your code, while using single quotes you will not need to escape double quotes and also there is an echo inside the links function so its not required here: <?php echo links(); ?>

edited Feb 18, 2015 at 0:31

William George

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answered Feb 17, 2015 at 17:02

Luca Olivieri

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1 Comment

thatidiotguy Over a year ago

This is not the cause of the problem the user is describing, though you are correct that the echo is unnecessary.

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