PHP: Output single array as multiple lists

Question

I have an array of unknown length:

$array = array('1', '2', '3', '4', '5', '6', '7', '8' ...);

I need to output this array as multiple lists, where a new list is created for every 3 array entries.

<ul>
  <li>1</li>
  <li>2</li>
  <li>3</li>
</ul>

<ul>
  <li>4</li>
  <li>5</li>
  <li>6</li>
</ul>

<ul>
  <li>7</li>
  <li>8</li>
</ul>

Note that I need to close the last list even if it does not contain 3 list-items.

Here is my attempt:

<?php for ($i = 0; $i < count($rows); ++$i): ?>

  <?php if (($i % 3) == 0): ?>
    <ul>
  <?php endif; ?>
    <li><?php print $rows[$i]; ?></li>
  <?php if (($i % 3) == 2): ?>
    </ul>
  <?php endif; ?>

<?php endfor; ?>

I think now you got various answers and all are very interesting, go trough each answer and choose one which works for you! — Rizier123
– Rizier123, Commented Feb 18, 2015 at 8:49

Kevin · Accepted Answer · 2015-02-18 08:46:39Z

5

You could utilize an array_chunk for this task. Chunk them by threes:

$array = range(1, 8);
$unknown_length = array_chunk($array, 3); // cut by batches of three
foreach($unknown_length as $ul) {
    echo '<ul>';
    foreach($ul as $li) {
        echo "<li>$li</li>";
    }
    echo '</ul>';
}

Sample Output

answered Feb 18, 2015 at 8:46

Kevin

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2 Comments

Rizier123 Over a year ago

array_chunk and very meaningful variable names that's a good example of code

Kevin Over a year ago

@Rizier123 i didn't thought about it actually, just first thing that popped out of my head while typing. lol :D.

Rizier123 · Accepted Answer · 2015-02-18 08:58:37Z

3

This should work for you:

(Here I split the array in chunks of 3 with array_chunk(). Then I loop through each innerArray with a foreach loop and print the lists with implode())

<?php

    $array = array('1', '2', '3', '4', '5', '6', '7', '8');

    foreach(array_chunk($array, 3) as $chunk) 
        echo "<ul><li>" . implode('</li><li>', $chunk) . "</li></ul>";

?>

edited Feb 18, 2015 at 8:58

answered Feb 18, 2015 at 8:46

Rizier123

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Comments

Rakesh Sharma · Accepted Answer · 2015-02-18 08:45:47Z

1

Try with foreach loop

$array = array('1', '2', '3', '4', '5', '6', '7', '8');
$i=1;
foreach($array as $a) {
  if($i == 1) echo '<ul>';
  echo '<li>'.$a.'</li>';
  if($i % 3 == 0) {
    echo '</ul>';
    echo '<ul>';
  }
  if($i == count($array))
    echo '</ul>';
  $i++;
}

output :-

<ul>
<li>1</li>
<li>2</li>
<li>3</li>
</ul>
<ul>
<li>4</li>
<li>5</li>
<li>6</li>
</ul>
<ul>
<li>7</li>
<li>8</li>
</ul>

answered Feb 18, 2015 at 8:45

Rakesh Sharma

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Comments

Epodax · Accepted Answer · 2015-02-18 08:55:36Z

1

$i = 1;
foreach($array as $value){
   switch($i){
      case 1:
         echo '<ul>' 
               . '<li>' . $value . '</li>';
         break;
      case 2:
         echo '<li>' . $value . '</li>';
         break;
      case 3:
         echo '<li>' . $value . '</li>'
              . '</ul>';
         $i = 0;
         break;
   }
   $i++;
}

edited Feb 18, 2015 at 8:55

answered Feb 18, 2015 at 8:49

Epodax

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2 Comments

Rizier123 Over a year ago

Okay one thing i have to admit here. You wrote the only answer i never would have thought of and i didn't expected it, but it's a very creative solution.

Epodax Over a year ago

Thanks! It's not very advanced or structural complex, but it works and is simple to understand. @Rizier123

Sadikhasan · Accepted Answer · 2015-02-18 08:53:49Z

0

$array = array('1', '2', '3', '4', '5', '6', '7', '8');
echo "<ul>";
foreach($array as $key => $val){

    echo "<li>$val</li>";

    if(($key+1)%3 == 0){
        echo "</ul><ul>";       
    }
}
echo "</ul>";

Demo

edited Feb 18, 2015 at 8:53

answered Feb 18, 2015 at 8:46

Sadikhasan

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Comments

Kartik Patel · Accepted Answer · 2015-02-18 08:56:52Z

0

$array = array('1', '2', '3', '4', '5', '6', '7', '8');

        $n = count($array);
        $i=1;
        $list = '';
        foreach ($array as $val) {

            if($i==1){
                $list .='<ul>';
            }
                $list .='<li>'.$val.'</li>';
            if($i%3==0){
                $list .='</ul>';
                $list .='<ul>';
            }

            if($n==$i){ $list .='</ul>'; }
            $i++;
        }
        echo $list;

answered Feb 18, 2015 at 8:56

Kartik Patel

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Comments

Alex Belyaev · Accepted Answer · 2015-02-18 09:05:04Z

0

Why not to use template-like alternative loop syntax right in HTML? (of course if you are using some kind of "views")

<? for ($i=0; $i<count($a); $i+=3): ?>
    <ul>
    <? for ($j=$i; $j<min(count($a), $i+3); $j++): ?>
        <li><? echo $a[$j]; ?></li>
    <? endfor; ?>
    </ul>
<? endfor; ?>

answered Feb 18, 2015 at 9:05

Alex Belyaev

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