Include PHP File and execute it multiple times

Question

Yeah I know this is probably not the best way to perform this. However I have a script which I would like to call multiple times with parameters and hand over two variables. The code I have so far looks like this:

$testfeld = array('User1'=>'400028',
                  'User2'=>'400027'
);

foreach($testfeld as $key=>$value) {
    $_GET['cmd'] = 'modify';
    include("testmodify.php");
}

If I run this code, I get an error message:

Fatal error: Cannot redeclare show() (previously declared in testmodify.php:14) in testmodify.php on line 39

If I perform this, it only modifys me the first entry of the array and then throws me the error message above. Sadly, I have only read access to testmodify.php.... So is there a way to perform this include with all the content of the array?

Does the file 'testmodify.php' define a function? If so then that is the cause of the error. Why not include the file once and refer to the function repeatedly? — Professor Abronsius
– Professor Abronsius, Commented Feb 20, 2015 at 13:04
Thats because you're redeclaring show(), instead of including it inside the foreach, include it above it, then run the function you want to run inside the loop... — user1897253
– user1897253, Commented Feb 20, 2015 at 13:05

MilanG · Accepted Answer · 2015-02-20 13:05:09Z

1

Put your code in the function, include it once and call as much as you want.

answered Feb 20, 2015 at 13:05

MilanG

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5 Comments

triplus Over a year ago

So you mean I can put all of the above code in the function in testmodify.php? The function is in the testmodify.php located. Am I right?

MilanG Over a year ago

What's in your testmodify.php move in some function inside the same file. Then include testmodify.php at begining of you script you shared here and from the loop instead of including just call your script.

triplus Over a year ago

Thank you for your help. Maybe its to easy and I don't get it. How do I call my script from the loop? My script has the name "testfile.php". The "show" definition is already a function in testmodify.php. I moved the include in testfile.php to the top of my script. Can you help me one more time? Thank you!

MilanG Over a year ago

Sorry, I don't know what exactly is inside your testmodify.php. If all code there is already inside some function then just include it once at the top and call the function from the place where include was. But if you have some code outside of any function then create some function, place the code in it, include file at the top and call the function from the place where you include file now.

triplus Over a year ago

Ok. I got it. Now it works very fine. Very much thanks for your support. I am not able to do a "Vote up".

Community · Accepted Answer · 2017-05-23 11:52:06Z

0

You are receiving this error because the file testmodify.php contains the definition for "show". A second inclusion of the file caused by your loop attempts to define the object show again, which cannot be done.

Here is another SO question about someone trying to redefine a function. Php and redifining

Edit: the other answer by MilanG is how you could go about fixing it.

edited May 23, 2017 at 11:52

CommunityBot

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answered Feb 20, 2015 at 13:07

Xeschylus

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Comments

Julio María Meca Hansen · Accepted Answer · 2015-02-20 14:06:45Z

0

You can do something like (in your testmodify.php script):

if (!function_exists("show")) {
    function show($parameters) {
        /* do your stuff here */
    }
}

A better thing to do, in this case, would be to perform include_once() in your testmodify.php script, making it point to a script file where you define your show() function. My approach should also work for you.

Hope that helps :)

answered Feb 20, 2015 at 14:06

Julio María Meca Hansen

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1 Comment

triplus Over a year ago

Thanks for your help. Sorry I didn't mention it before. The Definition of show() is already a function in the testmodify.php script.

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