I have the following C Code
#include <stdio.h>
int main(void){
char c[] = "ABC"
printf("%s ", c);
c[1] = 'B';
printf("%s", c);
return 0;
}
The output I want is ABC BBC but the output I get is ABC ABC. How can I replace the first character in an String / char array?
Indexing in C arrays start from 0. So you have to replace c[1] = 'B' with c[0] = 'B'.
Also, see similar question from today: Smiles in output C++ - I've put a more detailed description there :)
Below is a code that ACTUALLY WORKS!
char * replace_char(char * input, char find, char replace)
{
char * output = (char*)malloc(strlen(input));
for (int i = 0; i < strlen(input); i++)
{
if (input[i] == find) output[i] = replace;
else output[i] = input[i];
}
output[strlen(input)] = '\0';
return output;
}
C arrays are zero base. The first element of the array is in the zero'th position.
c[0] = 'B';
try
c[0] = 'B';
arrays start at 0
