php preg_replace Replace specific string with specific valus

Question

I studied following example

$copy_date = "Copyright 1999";
$copy_date = preg_replace("([0-9]+)", "2000", $copy_date);

 here any numeric will be replaced by 2000

But in following example I am confused !!

How to replace

width="anything" with value 280

Want to Substitute anything that appears after

   width="

with

   width="280"

example width="481" will be width="280"

Another example.....

 <iframe width="680" height="480" src="//www.youtube.com/embed/RTcgXcz-_G0" frameborder="0" allowfullscreen></iframe>

after preg_replace

should become

  <iframe width="280" height="200" src="//www.youtube.com/embed/RTcgXcz-_G0" frameborder="0" allowfullscreen></iframe>

Milad Nouri · Accepted Answer · 2015-02-21 19:30:46Z

1

use this:

$copy_date = '<iframe width="680" height="480" src="//www.youtube.com/embed/RTcgXcz-_G0" frameborder="0" allowfullscreen></iframe>' ;
$pattern = '/width="\d+"/i' ;
$new_style = 'width="280"' ;
$new_copy_date = preg_replace($pattern, $new_style, $copy_date) ;

echo $new_copy_date;

answered Feb 21, 2015 at 19:30

Milad Nouri

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