Understanding struct.unpack python

Question

test = struct.unpack('>%dH' % 1, '\x00\x44')

Is confusing me. I thought it means take the first 8 bytes and treat them as a double then take the next two and treat them as a short, and do all of that one time. But it means something else and I can't figure out what. It seems to realize that there is no double present and converts those two bytes to one number.

This code

test = struct.unpack('>1dH' , '\x00\x44')

Throws an error because it's expecting to find a double...

Can anyone tell me what the difference between these two are?

Thanks

unutbu · Accepted Answer · 2015-02-23 18:07:50Z

3

'>%dH' % 1 is equivalent to '>1H'.

>>> '>%dH' % 1
'>1H'

'>%dH' % 1 is using old-style string formatting to replace the %d with 1.

So the struct format is specifying a big-endian two-byte unsigned short.

edited Feb 23, 2015 at 18:07

answered Feb 22, 2015 at 19:30

unutbu

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