3

I have this code:

 import nltk
 import pypyodbc

 text = raw_input()
 token = nltk.word_tokenize(text) //return a list value


def search(self, lists):
    if not self.connected:
        self.connect()
    for word in lists:
        self.cur.execute('SELECT Ybanag FROM Words WHERE English IN (%s)' % (','.join('?'*len(lists))), lists)
        result = self.cur.fetchall()
        return result

wherein the output is a list of single element tuple (ex. I enter we all there): [('tore',), ('ngaming',), ('sittam',)] (translate the input into mother tongue language). I want that the output will be converted into string to eliminate the [],(),'',' symbols. How to convert it into string?

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2 Answers 2

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7

You have to use str.join method.

>>> a = [('tore',), ('ngaming',), ('sittam',)]
>>> " ".join([x[0] for x in a])
'tore ngaming sittam'
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7 Comments

@TomByler, it works, you can select it as answer. That will help others to find correct answer.
Another question is how can I convert the single element tuple into an array or how to store the string into an array variable?
You can convert using [x[0] for x in a]
Yes, is that not the same like in single element tuple - string conversion? What if instead of string, the result in this line result = self.cur.fetchall() will be stored in an array variable? Can I do this array[]=result?
@TomByler, better to ask another question with full details.
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0

I would just use a for loop. You can loop through the list of tuples and add each element to an empty string variable

x = [('tore'), ('ngaming'), ('sittam')]
z = ""
for i in x:
    z = z + i + " "

print z

After seeing Lafada's answer, I realized that list comprehension and str.join is the best option. Though his answer is better, this is basically what his answer does, just done more manually.

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