How to update the value of particular tag of XML file using shell script

Question

How I pass the arguments to sed command to replace a particular string . I want to replace 8080 with some different port like 8181 or 8282.

grep -rl 8080 /tmp/standalone.xml | xargs sed -i 's/8080/8181/g'

8181 is dynamic value. port="$1" grep -rl 8080 /tmp/standalone.xml | xargs sed -i 's/8080/"$port"/g' It will replace 8080 with "$port" not with the inputs — Sanojit
– Sanojit, Commented Feb 24, 2015 at 11:20
Just use double quotes: sed "s/8080/$port/g", this way the $port will be expanded to its actual value. — fedorqui
– fedorqui, Commented Feb 24, 2015 at 11:29
This is one where you have the correct tool for the job, and the question is "How do I use it?". Basic substitution is covered in a cursory fashion in the man page, but there are literally 100's of good sed tutorials/examples on the web. This is a valid question, but it is borderline between getting dinged for not doing due-diligence before asking the question. No downvotes, but be aware, stackoverflow, as a programming site, really encourages you to look before you ask. Just guidance for the future -- Welcome to SO — David C. Rankin
– David C. Rankin, Commented Feb 24, 2015 at 11:38

Paul Evans · Accepted Answer · 2015-02-24 11:38:40Z

1

You want to use double quotes instead of single as variables can then be expanded, something like:

 grep -rl 8080 /tmp/standalone.xml | xargs sed -i "s/8080/$port/g"

answered Feb 24, 2015 at 11:38

Paul Evans

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2 Comments

port=""$port"" this was coming instead of 8181 or 8222

What exact command are you running, @SANU ? It looks like you are using extra double quotes, while Paul's code should be more than enough.

candymanuu · Accepted Answer · 2015-02-24 13:09:43Z

0

You can sed directly

sed -i "s/$oldValue/$newValue/g" /tmp/standalone.xml

or

sed -i "s/8080/8181/g" /tmp/standalone.xml

answered Feb 24, 2015 at 13:09

candymanuu

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