Given a list like so:
[[1,2,3],[4,5,6],[7,8,9]]
I'm trying to get my output to look like this, with using only a list comprehension:
1 2 3
4 5 6
7 8 9
Right now I have this:
[print(x,end="") for row in myList for x in row]
This only outputs:
1 2 3 4 5 6 7 8 9
Is there a way to have it break to a new line after it processes each inner list?
You could do like the below.
>>> l = [[1,2,3],[4,5,6],[7,8,9]]
>>> for i in l:
print(' '.join(map(str, i)))
1 2 3
4 5 6
7 8 9
print(*i, sep=' ')?You can do as follows:
print("\n".join(" ".join(map(str, x)) for x in mylist))
Gives:
1 2 3
4 5 6
7 8 9
>>> l = [[1,2,3],[4,5,6],[7,8,9]]
>>> for line in l:
print(*line)
1 2 3
4 5 6
7 8 9
A good explanation of the star in this answer. tl;dr version: if line is [1, 2, 3], print(*line) is equivalent to print(1, 2, 3), which is distinct from print(line) which is print([1, 2, 3]).
I agree with Ashwini Chaudhary that using list comprehension to print is probably never the "right thing to do".
Marcin's answer is probably the best one-liner and Andrew's wins for readability.
For the sake of answering the question that was asked...
>>> from __future__ import print_function # python2.x only
>>> list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
>>> [print(*x, sep=' ') for x in list]
1 2 3
4 5 6
7 8 9
[None, None, None]
Try this:
print("\n".join([' '.join([str(val) for val in list]) for list in my_list]))
In [1]: my_list = [[1,2,3],[4,5,6],[7,8,9]]
In [2]: print("\n".join([' '.join([str(val) for val in list]) for list in my_list]))
1 2 3
4 5 6
7 8 9
print()is a function with side-effects, don't use it with comprehensions: Is it Pythonic to use list comprehensions for just side effects?