Passing a PHP variable using ajax

Question

I'm trying to pass a php variable from page1.html (which contains a php variable that I got from another form) to page2.php using ajax but it's not working, so I need your help.

code from page1.php:

<script>
var url = 'page2.php';
$("#save").click( function() {
    $.ajax({
        url : url,
        type: 'post',
        data : {
            admin : <?php echo $admin; ?>,
            gname : <?php echo $gname; ?>,
            filename : docname,
            content : encodeURIComponent(editor.getValue())
        }
    });
});
</script>

The datas filename and content are being sent successfully but admin and gname are not.

Thanks in advance.

UPDATE:

<?php
    if(isset($_GET['admin'])) {
    $admin = $_GET['admin'];
    }
    if(isset($_GET['gname'])) {
    $gname = $_GET['gname'];
    }
?>

This code is where I get the php variable that I want to send, from another form which is irrelevant to this question.

user3989103 · Accepted Answer · 2015-02-25 05:47:38Z

3

Here you go buddy, replace your script code with this.

<script>
var url = 'page2.php';
var admin = '<?php echo $admin; ?>';
var gname = '<?php echo $gname; ?>';
$("#save").click( function() {
    $.ajax({
        url : url,
        type: 'post',
        data : {
            admin : admin,
            gname : gname,
            filename : docname,
            content : encodeURIComponent(editor.getValue())
        }
    });
});
</script>

answered Feb 25, 2015 at 5:47

user3989103

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Comments

I'm Geeker · Accepted Answer · 2015-02-25 05:02:09Z

1

Youre using the type post so must use the $_POST in php

PHP

<?php
    if(isset($_POST['admin'])) {
    $admin = $_POST['admin'];
    }
    if(isset($_POST['gname'])) {
    $gname = $_POST['gname'];
    }
?>

answered Feb 25, 2015 at 5:02

I'm Geeker

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Comments

Juuso Elo-Rauta · Accepted Answer · 2015-02-25 05:00:14Z

0

You are using $_GET['admin'] which is used to fetch parameters delivered with GET method. You should be using $_POST['admin'] since you have set POST as your http request type in the JS code.

answered Feb 25, 2015 at 5:00

Juuso Elo-Rauta

294 bronze badges

5 Comments

John Over a year ago

NO, all the code above is in page1.php. The ajax will send the data to page2.php where I use $_POST['admin']. I'm using $_GET['admin'] to get the data that I want to send.

user3989103 Over a year ago

You can try alert to see whether you are getting value of admin variable or not.

John Over a year ago

@hrs I know its not being sent. I just want to know why is it not working.

user3989103 Over a year ago

Before starting AJAX, below var url; define new variable. var admin = '<?php echo $admin; ?>'; and then alert the admin.

John Over a year ago

@hrs The alert worked and displayed the variable, but its still not sending.

rGonzalez · Accepted Answer · 2015-02-25 05:03:49Z

0

As everyone is saying you're mixing POST and GET. But it caught another thing that may bother you. Are those variables strings? If they are, maybe you're missing the apostrophe/single quote.

<script>
var url = 'page2.php';
$("#save").click( function() {
$.ajax({
   url : url,
    type: 'post',
    data : {
        admin : '<?php echo $admin; ?>',
        gname : '<?php echo $gname; ?>',
        filename : docname,
        content : encodeURIComponent(editor.getValue())
    }
});
});
</script>>

answered Feb 25, 2015 at 5:03

rGonzalez

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3 Comments

rGonzalez Over a year ago

If the "page1.html" is html, it's impossible to get the php variables. Is the page1, the one that creating the javascript code, a php or html?

John Over a year ago

it's php. The variable working and displaying on page1.php but its not being sent to page2.php for some reason.

rGonzalez Over a year ago

Ok. just making sure. I would recommend you to use some tool, like firebug to make sure that variables are being sent. Good luck!

varad mayee · Accepted Answer · 2015-02-25 05:04:39Z

0

Your below code

<?php
    if(isset($_GET['admin'])) {
    $admin = $_GET['admin'];
    }
    if(isset($_GET['gname'])) {
    $gname = $_GET['gname'];
    }
?>

is to be replaced by

    <?php
    if(isset($_POST['admin'])) {
    $admin = $_POST['admin'];
    }
    if(isset($_POST['gname'])) {
    $gname = $_POST['gname'];
    }
?>

answered Feb 25, 2015 at 5:04

varad mayee

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Comments

Nishu Tayal · Accepted Answer · 2015-02-25 05:54:04Z

0

You are sending POST parameters,while using get in PHP script. And another issue is you are not using quotes with $admin and $gname variables in ajax request.
Try following :

<script>
var url = 'page2.php';
$("#save").click( function() {
    $.ajax({
        url : url,
        type: 'post',
        data : {
            admin : '<?php echo $admin; ?>',
            gname : '<?php echo $gname; ?>',
            filename : docname,
            content : encodeURIComponent(editor.getValue())

        }
    });
});
</script>

PHP Script:

<?php
    if(isset($_POST['admin'])) {
        $admin = $_POST['admin'];
    }
    if(isset($_POST['gname'])) {
        $gname = $_POST['gname'];
    }
?>

Check if it helps you.

answered Feb 25, 2015 at 5:54

Nishu Tayal

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