access variable containg spaces in bash script

Question

I need to create/access a directory contain spaces. I know that I can create in this way mkdir -p ' asd qwe'.

But I need to put that value to a variable and access it. Following will script create 2 directory as expected.

   FOL="asd qwe"    
   mkdir -p "$FOL"

But how can I assign that value to a single variable and do it?

Following will script create 2 directory as expected -- No the command creates a single directory named asd qwe — hek2mgl
– hek2mgl, Commented Feb 25, 2015 at 11:26
Sorry guys. It working for me also. I don't know why it was working for me initially. If I get to know why it was not working earlier I will update here. — nantitv
– nantitv, Commented Feb 25, 2015 at 11:37

Paul Evans · Accepted Answer · 2015-02-25 11:30:31Z

1

Exactly as you wrote it:

FOL="asd qwe"    
mkdir -p "$FOL"

will make a single directory called asd qwe

answered Feb 25, 2015 at 11:30

Paul Evans

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nantitv Over a year ago

Sorry guys. It working for me also. I don't know why it was working for me initially. If I get to know why it was not working earlier I will update here

candymanuu · Accepted Answer · 2015-02-25 11:31:17Z

0

your script is doing what you need

root@asd:~# FOL="asd qwe"
root@asd:~# mkdir -p "$FOL"
root@asd:~# ll
total 4
drwxr-xr-x 2 root root 4096 Feb 25 13:29 asd qwe

answered Feb 25, 2015 at 11:31

candymanuu

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