I want to implement regular express for below condition , can any one help please
Numeric 0-9 with special character/ \ @ # $ % ^ & * ! - ~ . _ ( ) & space allowed
like : 123abc not allowed
like : 123#$%~. are allowed
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3 Answers
You've pretty much wrote the regular expression yourself, you need to add those characters to a character class with proper escaping, use a quantifier and anchor your expression.
^[0-9/\\@#$%^&*!~._() -]+$
In C#, you can use the Regex.IsMatch() method to validate:
if (Regex.IsMatch(input, @"^[0-9/\\@#$%^&*!~._() -]+$")) { ... }
In JS, you can use the test() method to validate:
var re = /^[0-9/\\@#$%^&*!~._() -]+$/
if (re.test(input)) { ... }
Comments
Comments
For the regex itself, you should be able to pretty much list the allowed characters in square brackets:
^[0-9/\\@#$%^&*!-~._()\ ]*$
Use * at the end (before the trailing $) to match 0 or more characters (i.e. if empty string is OK), or use + at the end (before the trailing $) to match 1 or more characters.
Depending on the language / regex implementation, you might need to escape more of those characters within the pattern string.
2 Comments
Prashant Mehta
Thanks Paul for quick reply. it's taking alphabets value also like a,b,c,d....I want to disabled alphabets.
Paul Karlin
OK, so you want to match the full input. I've edited my answer above to include ^ at the beginning and $ at the end.
