PHP get result of function within echo

Question

I want to echo out the result of a function within the initial echo.

echo "<div class='booking-item-rating'>" . stars($hotelSummary[$x]['hotelRating']) . "</div>";

The function:

function stars($stars){
for($i=1;$i<=$stars;$i++) {
    echo "<i class='fa fa-star'></i>";
}
if (strpos($stars,'.')) {
    echo "<i class='fa fa-star-half-empty'></i>";
    $i++;
}
while ($i<=5) {
    echo "<i class='fa fa-star-o'></i>";
    $i++;
}
}

The problem is that the result of the function is printed outside the initial echo field, outside of the div element. How do I get the result of the function to print out within the first echo ?

in any context it is almost always a bad idea to have echo inside a function — user557846
– user557846, Commented Feb 26, 2015 at 23:35

John Conde · Accepted Answer · 2015-02-26 23:33:51Z

2

return that content instead of echoing it:

function stars($stars){
    $string = '';
    for($i=1;$i<=$stars;$i++) {
        $string .= "<i class='fa fa-star'></i>";
    }
    if (strpos($stars,'.')) {
        $string .= "<i class='fa fa-star-half-empty'></i>";
        $i++;
    }
    while ($i<=5) {
        $string .= "<i class='fa fa-star-o'></i>";
        $i++;
    }
    return $string;
}

answered Feb 26, 2015 at 23:33

John Conde

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