How to use an array twice in a php script

Question

I am working on a script and want to use an array called $states twice. $states is an array with a list of 50 states.

I am using the code snippet below to display the results. If I only use the div with class="table-responsive" by itself it works and displays correctly. If I only use the div with class="container" by itself it also displays the results correctly.

However, when I try using both together i.e. one following the other the first one works and the second one displays nothing or at most displays the last result in the array. I have tried resetting array but nothing seems to work.

What am I doing wrong? Any help would be appreciated. Thanks.

<div class="table-responsive" id="defaultview">

    <table  class="table"  width="100%"  border="0" cellspacing="0" cellpadding="0">
    <? array_shift($states);
    $rows3 = array_chunk($states, 2);
    foreach ($rows3 as $states) { ?>
    <tr>
    <? foreach($states as $state){ ?>

    <td><a href="/search.php?state=<?=$state['state']?>" title="<?=$state['state']?>">
    <?=$state['state']?>
    </a></td>
    <? } ?>
      </tr>
      <? }?>
    </table>

</div><!-- /End #state -->



<div class="container" id="smallview" style="padding-left: 1px;"> 
    <ul class="list-group">

    <? 
    reset($states);
    array_shift($states);
    foreach($states as $state)
    { ?>
    <li class="list-group-item"><a href="/search.php?state=<?=$state['state']?>" title="<?=$state['state']?>">
     <?=$state['state']?>
     </a></li>
     <? } ?>


     </ul>
 </div><!-- /End #state -->

reset() ? php.net/manual/en/function.reset.php - surely the answer's not actually in the title of the question? — CD001
– CD001, Commented Feb 27, 2015 at 0:46

Ja͢ck · Accepted Answer · 2015-02-27 02:45:56Z

1

The problem is here:

array_shift($states);
$rows3 = array_chunk($states, 2);
foreach ($rows3 as $states) {
//                 ^^^^^^^

At this point you overwrite the original $states array; if the original array had an odd number of elements, say 49, at the end of the loop you would now have a $states array with just one element.

Further in the code:

reset($states);
array_shift($states);

After array_shift() the array would now be empty.

edited Feb 27, 2015 at 2:45

answered Feb 27, 2015 at 2:37

Ja͢ck

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2 Comments

lawtalk Over a year ago

thank you so much. That is exactly what is happening. I am a newbie at all this. How would I fix this to make this work? Any suggestion would really be appreciated.

Ja͢ck Over a year ago

You can fix it by avoiding the same variable name as your original array, e.g. foreach ($rows3 as $row).

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