php read other php-file

Question

I have one php page (index.php) with following contents:

<php
    include("{$_SERVER['DOCUMENT_ROOT']}/somefunction.php")
    echo "hello world";
?>

Now I want to read the contents of index.php via another php-file (test.php) The result I want to get is:

line 1: include("{$_SERVER['DOCUMENT_ROOT']}/somefunction.php")
line 2: echo "hello world";

This is what I already tried, but it won't work:

$phppage="{$_SERVER['DOCUMENT_ROOT']}/index.php";
$handle = fopen($phppage, "r");
if ($handle) {
    while (($line = fgets($handle)) !== false) {
        // process the line read.
        echo $line;
    }
    fclose($handle);
}
else {
    // error opening the file.
    echo "An error occured";
}

It just echoes an empty string.

Problem solved :-)

I eventually want to put the lines in an array. I want my browser to show the php-code instead of hello world — Dude
– Dude, Commented Feb 27, 2015 at 10:30

Tintu C Raju · Accepted Answer · 2015-02-27 10:42:15Z

2

Actually your code is working. The problem is it will not displayed on browser . Since it contain html special character like <

So either print The result with in a <pre> </pre> tag.

or use htmlentities()

echo htmlentities($line);

or remove <?php ?> from the file index.php

answered Feb 27, 2015 at 10:42

Tintu C Raju

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1 Comment

Dude Over a year ago

Thx, that works! Sorry I can't vote you up... Still new here. Can someone else vote him up plz?

Community · Accepted Answer · 2017-05-23 12:22:14Z

0

When you say "it won't work" - do you get any error messages? Have you tried switching on error_reporting and display errors?

This is possibly security related - no permission to open the file.

Try using a relative path and double check that there are no basedir restrictions in place.

edited May 23, 2017 at 12:22

CommunityBot

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answered Feb 27, 2015 at 10:28

phpPhil

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Comments

phpfresher · Accepted Answer · 2015-02-27 10:34:52Z

0

Are you looking for this...

show_source()

This function shows your PHP code in the browser..

URL: http://www.w3schools.com/php/func_misc_show_source.asp

answered Feb 27, 2015 at 10:34

phpfresher

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2 Comments

Dude Over a year ago

That would be good, if I could put the lines of showsource in an array. I'll test it.

Dude Over a year ago

I can't get it in an array, so it's not useful to me. Thx anyway!

user4590533 · Accepted Answer · 2015-02-27 10:48:46Z

0

this is working try this 

read.php as 

<?php
$phppage=realpath("index.php");
$data = htmlentities(file_get_contents($phppage));
echo $data;

?>

index.php as

<?php

$absolute_path = realpath("somefunction.php");
include($absolute_path);
echo "hello world";
?>

answered Feb 27, 2015 at 10:48

user4590533

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1 Comment

Dude Over a year ago

I already tried something else, and that works, but this looks like a valiable alternative.

KIKO Software · Accepted Answer · 2015-02-27 12:43:58Z

0

If you don't need the line numbers, which are not made by your code, you could do:

readfile('index.php');

or

echo file_get_contents('index.php');

Which will work as long as you work in the same directory. If you need line numbers:

$lines = explode("\n",file_get_contents('index.php'));

foreach ($lines as $key => $line) echo "line {$key+1}: $line\n";

And if you don't want to echo, well, that's obvious.

edited Feb 27, 2015 at 12:43

answered Feb 27, 2015 at 10:27

KIKO Software

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1 Comment

Dude Over a year ago

There is an error in your code (you forgot the close ) on the first line :-)

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