JSON Encoding a map in Elixir using Poison

Question

I'm trying to parse my map into a json string, how would i do that using poison?

I've tried the following.

iex(19)> test = %{"api_key" => "sklfjklasfj"}
%{"api_key" => "sklfjklasfj"}
iex(20)> Poison.Encoder.encode(test, [])
[123, [[34, ["api_key"], 34], 58, [34, ["sklfjklasfj"], 34]], 125]

What i would expect was

"{"api_key": "sklfjklasfj"}"

Note you can also use Poison.encode/1 and Poison.decode/1 without touching Poison.Encoder. — whatyouhide
– whatyouhide, Commented Feb 27, 2015 at 13:44

xji · Accepted Answer · 2017-10-05 22:34:35Z

13

I realised poison was returning a char_list, which can be casted to a string like so.

iex(27)> to_string Poison.Encoder.encode(test, [])
"{\"api_key\":\"sklfjklasfj\"}"

As of October 2017 (Poison v3), the code would be

iex(27)> to_string Poison.encode_to_iodata!(test, [])
"{\"api_key\":\"sklfjklasfj\"}"

or simply

iex(27)> Poison.encode!(test, [])
"{\"api_key\":\"sklfjklasfj\"}"

without the to_string call.

edited Oct 5, 2017 at 22:34

xji

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answered Feb 27, 2015 at 12:09

MartinElvar

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3 Comments

Roger Lipscombe Over a year ago

It's not a char_list, which is just a flat list of code points; it's an IO list, which can be arbitrarily nested. You can send them directly as file or socket IO, and they'll get flattened when needed. See dev.af83.com/2012/01/16/erlang-iolist.html, for example.

xji Over a year ago

Note now in the newest version of Poison you'd use encode_to_iodata! instead of just encode.

xji Over a year ago

Or just use encode! and drop the to_string call.

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