PHP Loop Over ONLY Different Arrays

Question

I have a single array with several of the same values. And I only want to loop over DIFFERENT values. How could I go about doing this?

Example

166-01 001;09;UO;
166-01 001;09;UO;
166-01 001;09;UO;
166-01 001;09;UO;
166-01 001;09;UO;
166-01 001;09;UO;
166-01 001;09;UO;_86
166-01 001;09;UO;_86
166-01 001;09;UO;_86
166-01 001;09;UO;_86
166-01 001;09;UO;_86
166-01 001;09;UO;_86_97
166-01 001;09;UO;_86_97
166-01 001;09;UO;_86_97
166-01 001;09;UO;_86_97_108
166-01 001;09;UO;_86_97_108
166-01 001;09;UO;_86_97_108_119
166-01 001;09;UO;_86_97_108_119

I have that in a single array, but I only want to loop for the different ones. So it would loop once for nothing, then once for _86, then once for _86_97, then once for _86_97_108, and then once for _86-97_108_119. So only loop for different key values,

or would there be a way to count the number of different keys?

Community · Accepted Answer · 2023-11-17 20:38:18Z

3

array_unique()

foreach(array_unique($array) as $key => $value)

edited Nov 17, 2023 at 20:38

CommunityBot

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answered May 21, 2010 at 1:32

Tyler Carter

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Comments

too much php · Accepted Answer · 2010-05-21 01:34:31Z

0

I think you are looking for array_unique(), perhaps used in conjunction with array_keys().

answered May 21, 2010 at 1:34

too much php

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Comments

Alec · Accepted Answer · 2010-05-21 01:34:51Z

0

Keep track of the ones you've passed:


$passed = array();

foreach ($array as $value) {
  if (!in_array($value, $passed)) {
    $passed[] = $value;
  }
}

print_r($passed);

Or easier:

$array = array_unique($array);

answered May 21, 2010 at 1:34

Alec

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