An issue here to me that if i use parse string for the result of calculator program for instance,
4.5 * 5.0 = 22.5
how can I use splitting here to depart decimal part from result?
An issue here to me that if i use parse string for the result of calculator program for instance,
4.5 * 5.0 = 22.5
how can I use splitting here to depart decimal part from result?
Assuming you're working with strings only :
var str = "4.5 * 5.0 = 22.5 "
// Trim your string in order to remove whitespaces at start and end if there is any.
var trimmedStr = str.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
// Split the string by " " (whitespace)
var splitStr = trimmedStr.componentsSeparatedByString(" ")
// If the split was successful, retrieve the last past (your number result)
var lastPart = ""
if let result = splitStr.last {
lastPart = result
}
// Since it's a XX.X number, split it again by "." (point)
var splitLastPart = lastPart.componentsSeparatedByString(".")
// If the split was successful, retrieve the last past (your number decimal part)
var decimal = ""
if let result = splitLastPart.last {
decimal = result
}
count followed by last!, you should use if let syntax: if let result = splitStr.last { lastPart = result }. ! is dangerous and should only be used when there’s no practical alternative.Swift.split which is similar to componentsSeparatedByString: if let result = last(split(str) { $0 == " " }), let decimal = last(split(result) {$0 == "."}) { println(decimal) }Use modf to extract decimal part from result.
Objective-C :
double integral = 22.5;
double fractional = modf(integral, &integral);
NSLog(@"%f",fractional);
Swift :
var integral:Double = 22.5;
let fractional:Double = modf(integral,&integral);
println(fractional);
Want only interger part from double of float
Want only integer value from double then
let integerValue:Int = Int(integral)
println(integerValue)
Want only integer value from float then
let integerValue:Float = Float(integral)
println(integerValue)