I have a string containing time stamp in format
(DD/MM/YYYY HH:MM:SS AM/PM), e.g."12/20/2014 15:25:05 pm"
. The time here is in 24 Hrs format.
I need to convert into same format but with time in 12-Hrs format.
I am using python version 2.6.
I have gone through time library of python but couldn't come up with any solution.
View Live ideOne use Python datetime,
>>> from datetime import datetime as dt
>>> date_str='12/20/2014 15:25:05 pm'
>>> date_obj = dt.strptime(date_str, '%m/%d/%Y %H:%M:%S %p')
>>> dt.strftime(date_obj, '%m/%d/%Y %I:%M:%S %p')
'12/20/2014 03:25:05 PM'
from datetime that why not worked, now worked correctly.The trick is to convert your Input date string to Python datetime object and then convert it back to date string
import datetime
#Input Date String
t = "12/20/2014 15:25:05 pm"
#Return a datetime corresponding to date string
dateTimeObject = datetime.datetime.strptime(t, '%m/%d/%Y %H:%M:%S %p')
print dateTimeObject
Output: 2014-12-20 15:25:05
#Return a string representing the date
dateTimeString = datetime.datetime.strftime(dateTimeObject, '%m/%d/%Y %I:%M:%S %p')
print dateTimeString
Output: 12/20/2014 03:25:05 PM
After creating a datetime object using strptime you then call strftime and pass the desired format as a string see the docs:
In [162]:
t = "12/20/2014 15:25:05 pm"
dt.datetime.strftime(dt.datetime.strptime(t, '%m/%d/%Y %H:%M:%S %p'), '%m/%d/%Y %I:%M:%S %p')
Out[162]:
'12/20/2014 03:25:05 PM'
I really appreciate & admire (coz I barely manage to read man pages :P) you going through time documentation, but why use "astonishing" & "cryptic" code when simple code could get the job done
Just extract the hour part as int & replace it by hrs-12 if it is greater than 12
t = "12/20/2014 15:25:05 pm"
hrs = int( t.split()[1][:2] )
if hrs > 12:
t = t.replace( str(hrs), str(hrs-12) )
See explaination & live output here
If you like one liners, checkout f() below
t = "12/20/2014 15:25:05 pm"
f = lambda tym: tym.replace(str(int(tym.split()[1][:2])), str(int(tym.split()[1][:2])-12)) if int(tym.split()[1][:2]) > 12 else tym
print(f(t))
