How can I get a class from a jQuery datatable row object?

Question

I have a jQuery datatable row:

 table = $('#reports').DataTable()
 row = table.row(rowIndex)

How do I get the HTML class from it? (It is striped, and I want to find out if it is odd or even.)

I have tried:

row.hasClass('odd')

row.className

row.attr('class')

Any ideas?

Rick Hitchcock · Accepted Answer · 2015-03-06 23:57:50Z

7

Use node with className:

row.node().className;

answered Mar 6, 2015 at 23:57

Rick Hitchcock

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5 Comments

Rick Hitchcock Over a year ago

Thanks :) DataTables documentation does leave something to be desired.

davidkonrad Over a year ago

The solution used in the fiddle for my now deleted answer here -> jsfiddle.net/d9r5n0hp

Rick Hitchcock Over a year ago

@davidkonrad, your answer may actually be better. Try mine with row 4. I get nothing, while you get "odd."

davidkonrad Over a year ago

Have undeleted my answer, but still thinks yours are better. Have not tested in depth. jsfiddle.net/d9r5n0hp/1

davidkonrad Over a year ago

Hmm. You are right. It is in fact a very, very good question. Have to go to bed, but will tomorrow look into what the he** I have done myself, for this particular situation. I know I have been here before.

Peter Mortensen · Accepted Answer · 2020-01-26 15:27:25Z

3

It is a really a good question. The ordinary jQuery way, by using row.index():

var rowClass = $("#example tbody tr:eq(" + row.index() + ")").attr('class');

Proof of concept -> http://jsfiddle.net/7jy46wz4/

edited Jan 26, 2020 at 15:27

Peter Mortensen

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answered Mar 6, 2015 at 23:35

davidkonrad

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Comments

Jonathan Queipo · Accepted Answer · 2016-10-21 22:57:38Z

0

Taking what @rick-hitchcock said, another approach is to use the following code in validations:

var hasOddClass = $(row.node).hasClass("odd");

which, by the examples you gave, should be closer to what you want.

answered Oct 21, 2016 at 22:57

Jonathan Queipo

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