Create a Dynamic UI in Android from json Template

Question

On the App start, I will download the data from the web-server and store it in shared-preference, now what I want is depending upon the json template dynamically create the UI form/Activity in android.Can any one suggest me how to implement this.

 {  
       "templates":[  
          {  
             "name":"Default",
             "default":true,
             "fields":[  
                {  
                   "type":"textbox",
                   "label":"Your e-mail",
                   "metadataIPTC":"234",
                   "required":true,
                   "regex":"\\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\\.[A-Z]{2,4}\\b"
                }
             ]
          }
       ]
    }

As I'm trying to create, it is first time implementing this, if there are any tutorial/example you can provide me @ianhanniballake — vinay Maneti
– vinay Maneti, Commented Mar 8, 2015 at 7:05
Have a look on this https://stackoverflow.com/questions/65086448/react-native-server-driven-ui/68200157#68200157 — Debdutta Panda
– Debdutta Panda, Commented Jun 30, 2021 at 19:09

Community · Accepted Answer · 2016-09-09 14:59:51Z

4

XML layouts are converted to Java objects at runtime, so you can simply write an XML which has a container Layout ( say Linear Layout ), inflate it at runtime, and add view programatically depending on the information received from server.

An example would be :
Creating a layout, and setting that as the Activity's content view.

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical"
    android:id="@+id/container"
   />

Then somewhere in code:
Let's say that after parsing the JSON you have a List<Field> fields;

  LinearLayout linearLayout = (LinearLayout) findViewById(R.id.container);
  for (Field f: fields) {
    if (f.getType().equals("textbox")) {
        TextView txtView = new TextView(this);
        txtView.setText("Your e-mail");
        txtView.setId(1);//need for better use
        linearLayout.addView(txtView);
    } else if (f.getType().equals("button")) {
        //create a button similarly as above,and add it to the layout
    }
  }

edited Sep 9, 2016 at 14:59

CommunityBot

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answered Mar 8, 2015 at 6:56

Rick Sanchez

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5 Comments

vinay Maneti Over a year ago

Can you please provide a sample example.

Rick Sanchez Over a year ago

About parsing the Json ?

vinay Maneti Over a year ago

I know parsing json, but the problem how to show the UI

bhautikmewada191 Over a year ago

can we have to check for each controls?

M.Yogeshwaran Over a year ago

how to fetch value from this please somebody tell me

halfer · Accepted Answer · 2021-02-08 00:27:15Z

1

I think you’re asking about Server Driven UI, please go through this link to know more about it: https://proandroiddev.com/dynamic-screens-using-server-driven-ui-in-android-262f1e7875c1

edited Feb 8, 2021 at 0:27

halfer

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answered Feb 7, 2021 at 18:30

syed dastagir

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1 Comment

halfer Over a year ago

Could you edit this answer to add a synopsis about what the link says? We generally discourage link-only answers, since the inevitable link rot can render answers useless if there is no other information.

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