I have string which can be one of the following two formats :
dts12931212112 : some random message1 : abc, xyz
nodts : some random message2
I need to extract substring from these two string which doesn't have 'dts' part i.e. it should return :
some random message1 : abc, xyz
some random message2
I need to do this inside a bash script.
Can you help me with the awk command, which does this operation for both kind of strings?
Through awk's gsub function.
$ awk '{gsub(/^[^:]*dts[^:]*:|:[^:]*dts[^:]*/, "")}1' file
some random message1 : abc, xyz
some random message2
$ awk '{gsub(/^[^:]*dts[^:]*:[[:blank:]]*|:[^:]*dts[^:]*/, "")}1' file
some random message1 : abc, xyz
some random message2
You could apply the same regex in sed also, but you need to enable -r --regexp-extended parameter.
^ asserts that we are at the start. [^:]* negated character class which matches any character but not of :, zero or more times. So this ^[^:]*dts[^:]*: would match the substring at the start which contain dts. It it won't touch if the substring is present at the middle. This :[^:]*dts[^:]* pattern matches the middle or last substring which has dts. Finally replacing the matched chars with an empty string will give you the desired output.
Update:
$ awk '{gsub(/^[^[:space:]]*dts[^[:space:]]*[[:space:]:]*|[[:space:]:]*[^[:space:]]*dts[^[:space:]]*/, "")}1' file
some random message1 : abc, xyz
some random message2
[[:blank:]] also instead of [[:space:]] where blank matches any horizontal white space character( whitespace,tab) where space matches both horizontal and vertical whitespace character (space,tab,newline,carriage return).Here is another awk
awk -F" : " '{$1="";sub(FS,"")}1' OFS=" : " file
some random message1 : abc, xyz
some random message2
Just remove first field when separated by :
Another version:
awk -F" : " '{print substr($0,index($0,$2))}' file
some random message1 : abc, xyz
some random message2
Get all data from second field and out separated by :