I have two classes:
abstract class A
{
private int a;
protected int get(){return a;}
}
class B extends A
{
private int a = 2;
}
What i want is to inherit get() method which would give me the result 2 instead of 0. I know why this code is not working but have no idea is it even possible to make this kind of trick in java.
If you don't want to override your get() method, you could pass the value to your a attribute in the constructor:
abstract class A {
private int a;
protected A(int a) {
this.a = a;
}
protected int get() {
return this.a;
}
}
class B
extends A {
B() {
super(2);
}
public static void main(String[] args) {
B b = new B();
System.out.println(b.get()); // 2
}
}
A is abstract, so you cannot instantiate any instance of A, but only of its non-abstract subclasses. Regarding your question: yes, you can pass any arguments in the constructor and assign them to the attributes, as long as there exists a constructor that actually accepts those arguments (that's why I created a protected constructor in A that accepts an int).You can override get() in class B :
class B extends A
{
private int a = 2;
@Override
protected int get() {
return a;
}
}
This way, calling get() on an instance of class B would return the a member of B.
a member, since you can't override a member. If you want to return B's a member, you must override get().If you an accessor such as getA() you can use get() with all of it's functionality as long as any code inside the definition of get() uses getA() to get the value of a instead of just using a.
Small example:
abstract class A
{
private int a;
protected int get(){
// do anything with getA(), here just return the value as in your question.
return getA();
}
public int getA(){ return a; }
}
class B extends A
{
private int a = 2;
@Override
public int getA(){ return a; }
}
