call two function by Inheritance in javascript

Question

I'm new for OOPS JavaScript. Be clear. See my JavaScript code here,

function a(){
    this.first = "Kar";
}
function b(){
    this.last = "Sho";
}
function c(){
    this.getName = function(){
        return this.first+this.last;
    }
}

c.prototype.u = new a();
c.prototype.v = new b();

var d = new c();

alert(d.getName());

Here, I'm getting following output,

NaN

But I want to print KarSho. Where is problem?

I know following method,

b.prototype = new a();
c.prototype = new b();

Actually what I want is, just call a and b in c. That's it.

user400654 · Accepted Answer · 2015-03-11 17:32:39Z

2

Call both a and b in the c constructor.

function a(){
    this.first = "Kar";
}
function b(){
    this.last = "Sho";
}
function c(){
    a.call(this);
    b.call(this);
    this.getName = function(){
        return this.first+this.last;
    }
}

var d = new c();

alert(d.getName());

answered Mar 11, 2015 at 17:32

user400654

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Comments

Jite · Accepted Answer · 2015-03-11 17:33:54Z

1

c.prototype.u = new a();
c.prototype.v = new b();

Creates instances of the a and b object on the c.v and c.u prototype properties.

To access them, you would call them by:

function c(){
  this.getName = function(){
    return this.v.first + this.u.last;
  }
}

This is not really inheritance, but rather assigning of properties.

answered Mar 11, 2015 at 17:33

Jite

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