PHP String Encoding Error

Question

I'm trying to get the following code to output an IMG tag with the URL for Google Static Maps API http://code.google.com/apis/maps/documentation/staticmaps/#Imagesizes embedded in there... the result is that everything except the $address is being output successfully... what am I doing wrong?

function event_map_img($echo = true){
    global $post;
    $address = get_post_meta($post->ID, 'date_address', true);
    if($echo): echo '<img src="'.'http://maps.google.com/maps/api/staticmap?center='.$address.'&zoom=14&size=700x512&maptype=roadmap&markers=color:blue|label:X|'.$address.'&sensor=false" />';
    else:
        return '<img src="'.'http://maps.google.com/maps/api/staticmap?center='.$address.'&zoom=14&size=700x512&maptype=roadmap&markers=color:blue|label:X|'.$address.'&sensor=false" />';
    endif;
}

What's the function get_post_meta returning? Add var_dump(get_post_meta($post->ID, 'date_address', true)); I have a feeling that it's returning nothing ('' or null) — ircmaxell
– ircmaxell, Commented May 24, 2010 at 20:58
sorry guys date_address was supposed to be "_date_address" so it was totally unrelated :( — Brian
– Brian, Commented May 24, 2010 at 21:04

Gumbo · Accepted Answer · 2010-05-24 20:57:43Z

1

Try this:

function event_map_img($echo = true) {
    global $post;
    $address = urlencode(get_post_meta($post->ID, 'date_address', true));
    $src = htmlspecialchars('http://maps.google.com/maps/api/staticmap?center='.$address.'&zoom=14&size=700x512&maptype=roadmap&markers=color:blue|label:X|'.$address.'&sensor=false');
    if ($echo) {
        echo '<img src="'.$src.'" />';
    } else {
        return '<img src="'.$src.'" />';
    }
}

answered May 24, 2010 at 20:57

Gumbo

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1 Comment

Brian Over a year ago

the problem was actually unrelated, sorry for buggin' ya, but you get a gold star anyway since you're right...

Web Logic · Accepted Answer · 2010-05-24 20:59:26Z

0

I think you are missing the & separator for $address after blue|label:X|, it should be like:

'&address=' . $address

answered May 24, 2010 at 20:59

Web Logic

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