Python - output not coming after parsing command line options

Question

Below is my code, where I am not getting output... after running script with inputfile and output file...

def parseCommandLine(argv=[]):
    inputfile = ''
    outputfile = ''
    FCSNAME = ''

    try:
        opts, args = getopt.getopt(
            argv,
            "hiop", 
            [help,"ifile=","ofile=","pcsfile="])
    except getopt.GetoptError,msg:
        printUsage()
        print "-E-Badly formed command line vishal!"
        print "  ",msg
        sys.exit(1)

    #Processing command line arguments
    for opt, arg in opts:
        opt= opt.lower()

        # Help
        if opt in ("-h", "--help"):
            printUsage()
            sys.exit()
        elif opt in ("-i", "--ifile"):
            inputfile = arg
        elif opt in ("-o", "--ofile"):
            outputfile = arg
        elif opt in ("-p", "--pcsname"):
            PCSNAME = arg
        if opt in ("-v"):
            VERBOSE = 1    
    print 'Input file is "', inputfile
    print 'Output file is "', outputfile
    print 'PCS NAME is "', FCSNAME
            # Verbose


    return 0

Output: ./aaa_scr -i list -o vishal

Input file is " Output file is " FCS NAME is "

No output is coming.. please help.

Please help.. your help is appreciated.

Vishal Mahajan
– Vishal Mahajan

2015-03-12 06:57:14 +00:00
Commented Mar 12, 2015 at 6:57 — Vishal Mahajan
– Vishal Mahajan, Commented Mar 12, 2015 at 6:57

Hussain · Accepted Answer · 2015-03-12 07:14:53Z

3

Exclude the 0th element from sys.argv. i.e. the program name.

import getopt
import sys
try:
    opts, args = getopt.getopt(
        sys.argv[1:],
        "i:o:p:",
        ["ifile=","ofile=","pcsfile="])
except getopt.GetoptError,msg:
    print "error : %s" % msg

inputfile, outputfile, FCSNAME = None, None, None
for opt, arg in opts:
    print opt, arg
    if opt in ("-i", "--ifile"):
        inputfile = arg
    elif opt in ("-o", "--ofile"):
        outputfile = arg
    elif opt in ("-p", "--pcsname"):
        FCSNAME = arg

print "inputfile %s" % inputfile
print "outputfile %s" % outputfile
print "FCSNAME %s" % FCSNAME

Also you have options that require an argument, so you need to handle those using : (colon)

I hope this helps.

edited Mar 12, 2015 at 7:14

answered Mar 12, 2015 at 7:02

Hussain

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Comments

Vinod Sharma · Accepted Answer · 2015-03-12 07:11:09Z

0th element of sys.argv list is the name of program which getopt don't like. So just remove it and then pass argv it to the getopt.

import sys 
import getopt

def printUsage():
      print "Usage"

def parseCommandLine(argv=[]):
    argv = argv[1:]
    inputfile = ''
    outputfile = ''
    PCSNAME = ''

    try:
          opts, args = getopt.getopt(argv, 'hi:o:p:')
    except getopt.GetoptError,msg:
        printUsage()
        print "-E-Badly formed command line vishal!"
        print "  ",msg
        sys.exit(1)

    #Processing command line arguments
    #print opts
    for opt, arg in opts:
        opt = opt.lower()

        # Help
        if opt in ("-h", "--help"):
            printUsage()
            sys.exit()
        elif opt in ("-i", "--ifile"):
            inputfile = arg 
        elif opt in ("-o", "--ofile"):
            outputfile = arg 
        elif opt in ("-p", "--pcsname"):
            PCSNAME = arg 
        if opt in ("-v"):
            VERBOSE = 1 
    print 'Input file is "', inputfile
    print 'Output file is "', outputfile
    print 'PCS NAME is "', PCSNAME

parseCommandLine(sys.argv)

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