Integer array of variable length

Question

I have a

int val,i;
scanf("%d",&val);
int a[] = { (val & 0x7) , (val & 0x5) };
for(i=0;i<2;i++)
printf("%d\n",a[i]);

I am confused whether the above code is good or not? I get this error on some compiler

expression must have a constant value

but on another this works fine.So is this code good?

How many elements does a have? If you need two, why not to define int a[2]? — a3mlord
– a3mlord, Commented Mar 12, 2015 at 11:07

Community · Accepted Answer · 2020-06-20 09:12:55Z

4

Variables in initializer list is not allowed before C99.

C89: 6.5.7:

All the expression in an initializer for an object that has static storage duration or in an initializer list for an object that has aggregate or union type shall be constant expressions.

From C99, it is allowed. Make sure you are compiling with -std=c99 flag.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Mar 12, 2015 at 11:13

haccks

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Integer array of variable length

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C89: 6.5.7:

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