I want to match aaa bbb and bbb aaa in the following string:
aaa bbb bbb aaa
using
match = re.search("^(?=.*(aaa))(?=.*?(bbb)).*$", subject, re.DOTALL | re.IGNORECASE)
see https://www.regex101.com/r/vA0nB0/2
But it only match aaa bbb.
How can I match bbb aaa too?
You could try the below simple regex.
>>> import re
>>> s = 'aaa bbb bbb aaa'
>>> re.findall(r'aaa.*?bbb|bbb.*?aaa', s)
['aaa bbb', 'bbb aaa']
If Python supports conditionals:
For out of order stuff, just use a conditional.
Note - change the quantifier in the group to reflect how many items
are required to match. Below shows {2} which requires both items somewhere.
You could change it to {1,} - at least 1, or + - same thing.
(?:.*?(?:((?(1)(?!))aaa.*?bbb)|((?(2)(?!))bbb.*?aaa))){2}
(?:
.*?
(?:
( # (1)
(?(1)
(?!)
)
aaa .*? bbb
)
| ( # (2)
(?(2)
(?!)
)
bbb .*? aaa
)
)
){2}
Output:
** Grp 0 - ( pos 0 , len 21 )
aaa bbb bbb aaa
** Grp 1 - ( pos 0 , len 8 )
aaa bbb
** Grp 2 - ( pos 11 , len 10 )
bbb aaa
How about something like this, if you know that its always going to be aaa or bbb?
>>> a = 'aaa bbb bbb aaa'
>>> match = re.findall("(aaa|bbb).+?(aaa|bbb)", a, re.DOTALL | re.IGNORECASE)
>>> match
[('aaa', 'bbb'), ('bbb', 'aaa')]
Here is the regex101 link : https://www.regex101.com/r/qO3uD3/1
aaa aaa in aaa aaa bbb.