PHP check if the function returns boolean

Question

So I got this function:

function hosting(){
    $localhostIP = array(
        '127.0.0.1',
        '::1'
    );
    if(!in_array($_SERVER['REMOTE_ADDR'], $localhostIP)){
        $localhost = false;
        return true;
    }else{
        $localhost = true;
        return $localhost;
    }
}

Later in the same file I want to call the function and check if the $localhost is true or false, this is what I got so far:

hosting();
if ($localhost == false) {
    echo"N";
}else{
   echo"Y";
}

It doesn't work and it is probably worst attempt ever, could someone show me how to check $localhost in the right way?

Thanks, Brian

did you try $localhost = hosting()

Stephen Reindl
– Stephen Reindl

2015-03-15 23:38:30 +00:00
Commented Mar 15, 2015 at 23:38 — Stephen Reindl
– Stephen Reindl, Commented Mar 15, 2015 at 23:38

John Conde · Accepted Answer · 2015-03-15 22:41:23Z

1

You need to assign the return value from the function call to a variable:

$localhost = hosting();
if ($localhost == false) {
    echo"N";
}else{
   echo"Y";
}

edited Mar 15, 2015 at 22:41

answered Mar 15, 2015 at 22:35

John Conde

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3 Comments

Brian Over a year ago

Thanks, works fine now. Just one more question how can I check if the function is true or false if its written like this:function hosting(){ $localhostIP = array( '127.0.0.1', '::1' ); if(!in_array($_SERVER['REMOTE_ADDR'], $localhostIP)){ return true; }else{ return false; } }

John Conde Over a year ago

Your question does not make any sense. Your code exactly what you're aksing.

Brian Over a year ago

Sorry, here: sandbox.onlinephpfunctions.com/code/… this time there is no $localhost, just {return true;}. How can I check that? Edit: Link works fine now

Ugur · Accepted Answer · 2015-03-15 22:52:24Z

0

A better approach may be;

function isLocalhost($ipAddress) {
    $localhostIP = array(
        '127.0.0.1',
        '::1'
    );

    return in_array($ipAddress, $localhostIP);
}

//To check whether the request coming from localhost or not

if(isLocalhost($_SERVER['REMOTE_ADDR'])) {
   echo "Localhost";
} else {
   echo "Not Localhost";
}

answered Mar 15, 2015 at 22:52

Ugur

1,72914 silver badges20 bronze badges

1 Comment

Brian Over a year ago

Thanks for sharing, looks like much better solution!

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