Pass variable to Ipython Widget

Question

I have a simple widget that modifies a plot, here is the definition:

#Plot function
def plf(x,lm,ls):
    plt.plot(x[lm:ls],np.sin(x)[lm:ls])

this function takes a list x an plot sin(x), lm and ls controls the number of data that is ploted, the problem is when i try to plot a determinated list of data, for example

list = [1,2,3,4,5,6,7,8,9]

and if i try

interact(plf,x=list,lm=(0,max(x)//2,1),ls=(max(x)//2,max(x),1))

throws me the error:

NameError: name 'x' is not defined

so, how can i define x so it can be any list that i want?

cel · Accepted Answer · 2015-03-16 06:44:48Z

3

Is this what you are trying to do?

%matplotlib inline
from IPython.html.widgets import interact, fixed
import matplotlib.pyplot as plt
import numpy as np

def plf(x,lm,ls):
    plt.plot(x[lm:ls],np.sin(x)[lm:ls])

data = [1,2,3,4,5,6,7,8,9]
max_lm = max(data)//2
max_ls = max(data)

interact(plf,x=fixed(data),lm=(0,max_lm,1),ls=(max_lm, max_ls,1))

answered Mar 16, 2015 at 6:44

cel

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1 Comment

Isak Baizley Over a year ago

Ohhh thaks, this is exactly what i wanted

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