How can I return a php code from a php function?

Question

<?php 
    function A() {
        return "<?php echo \"some text\"; ?>";
    }
    echo A();
?>

I expected to see "some text" on the page, but i did not. So how do I make this code work? Thanks in advance.

UPD: I'm sorry for the not clear description. I'm going to insert a random number into the value of the input.

<?php 
 function print_form() {
    return "<form method=\"POST\">
    <input type=\"text\" name=\"code1\" value=\" <?php echo rand(0, 999999); ?> \" />
    </form>"; 
 }
    echo print_form(); ?>

I think real question is "how do you insert a block of PHP code as the result of a function? I think you should consider using includes. php.net/manual/en/function.include.php — Glenn Ferrie
– Glenn Ferrie, Commented Mar 16, 2015 at 17:12

AbraCadaver · Accepted Answer · 2015-03-16 17:16:53Z

1

Concatenate the return of the function:

return "<form method=\"POST\">
<input type=\"text\" name=\"code1\" value=\"" . rand(0, 999999) . "\" />
</form>";

answered Mar 16, 2015 at 17:16

AbraCadaver

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Comments

Sofiane Sadi · Accepted Answer · 2015-03-16 16:59:01Z

1

mate you have to return the text not a PHP code:

<?php 
    function A() {
        return "some text";
    }
    echo A();
?>

answered Mar 16, 2015 at 16:59

Sofiane Sadi

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2 Comments

itachi Over a year ago

this is not the answer according to the question. he wants to run the code inside the function and return the output. not just output the string.

jeroen Over a year ago

@itachi Not really: I expected to see "some text" on the page

itachi · Accepted Answer · 2015-03-16 17:19:58Z

-1

<?php 
 function print_form() {
    return '<form method="POST">
    <input type="text" name="code1" value="'.rand(0, 999999).'" />
    </form>'; 
 }
    echo print_form(); ?>

you are returning, so just concatenent the value.

answered Mar 16, 2015 at 17:19

itachi

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