Using php how can I update a row in mysql database based on a forms input value?

Question

I have a form that has various inputs. One of the inputs contains a pre determined value that is loaded by script that is named "invoiceid". This invoiceid is the name and id of the form input and also the name of a column in my database. How can update the row in my database that contains the same value under the invoiceid column with all other form data submitted? I dont know what I'm doing...please help. Thanks for your time.

FORM

<form action="update.php" id="contactForm" method="post">

<input id="invoiceid" name="invoiceid" type="hidden" value=""/>

<input id="txt1" name="txt1" type="text" value=""/>

<input id="q1" name="q1" value="9.50" checked="checked" type="radio">
<input id="q1" name="q1" value="12.50" type="radio">

<select id="selectbox" name="selectbox">
<option selected="selected" value="">Please select...</option> 
 <option value="PURCHASE">Order for Purchase</option>
 <option value="REVIEW">Order for Review</option>
</select>

<button id="btn1" type="submit" name="submit">Submit</button></div>   

</form>

update.php

//Table name: seguin_orders

<?php

// Create the connection to the database
$con=mysqli_connect("xxx","xxx","xxx","xxx");


// Check if the connection failed
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  die();
}

   if (isset($_GET['invoiceid']))
{
    $invoiceid= $_GET['invoiceid'];



}
?>

if you use a POST method to submit a form, then you must use $_POST to get the value. For example $invoiceid = $_POST['invoiceid'] — Christian
– Christian, Commented Mar 19, 2015 at 1:56
Also it is worth noting that inputting raw $_POST data to a database leaves you vulnerable to SQL injection, which could result in a database breach (or worse). Be sure to familiarize yourself with this article beforehand, so that you will know how to make your program more secure :) — pattyd
– pattyd, Commented Mar 19, 2015 at 2:52

Adrian Cid Almaguer · Accepted Answer · 2015-03-19 03:22:02Z

1

I think it can help you.

update.php

<?php
   // Create the connection to the database
   $con=mysqli_connect("xxx","xxx","xxx","xxx");

  // Check if the connection failed
  if (mysqli_connect_errno()) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    die();
   }

  if (isset($_POST['invoiceid']))
  {
   $invoiceid= $_POST['invoiceid'];
   $column1 = $_POST['txt1']; 
   $column2 = $_POST['q1'];
   $column3 = $_POST['selectbox'];
   $sql = "UPDATE TableName SET column1='".$column1."', column2='".$column2."', column3='".$column3."' WHERE invoiceid='".$invoiceid."'";
  }
?>

///note: change the table name and column names according to your database

edited Mar 19, 2015 at 3:22

Adrian Cid Almaguer

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answered Mar 19, 2015 at 2:36

Sujan Shrestha

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