You misunderstood what \xhh does in Python strings. Using \x notation in Python strings is just syntax to produce certain codepoints.
You can use '\x61' to produce a string, or you can use 'a'; both are just two ways of saying give me a string with a character with hexadecimal value 61, e.g. the a ASCII character:
>>> b'\x61'
'a'
>>> b'a'
'a'
>>> b'a' == b'\x61'
True
The \xhh syntax then, is not the value; there is no \ and no x and no 6 and 1 character in the final result.
You should just write your bytestring:
somestring = b'abcd'
with open("test.bin", "wb") as file:
file.write(somestring.encode())
Note that I used bytestrings (b'...') in my code examples here. 'Regular' strings are Unicode data and cannot just be written to a binary file without encoding. The \x.. same escaping syntax works in normal literal string syntax too, but then you need to encode your string to bytes when writing:
somestring = '\x61bcd' # value: 'abcd'
with open("test.bin", "wb") as file:
file.write(somestring.encode('ascii'))
You certainly do not have to produce hexadecimal escapes to write binary data. Just because some binary file viewers represent data in a file as hexadecimal doesn't mean that the data is written in hexadecimal form!
Originally, this answer was written with Python 2 in mind, where the distinction between a binary and regular text file was less pronounced. There, the only difference with a file opened in text mode is that a binary file will not automatically translate \n newlines to the line separator standard for your platform; e.g. on Windows writing \n produces \r\n instead.
\xhhnotation for (and it is just syntax, a way to produce a value, not the value itself).'abcd'. On Python 3, you'd need to encode text to bytes withstr.encode('ascii').