Yes, I know I can do
python2 cal.py
What I am asking for is a way to execute it on the command line such as:
calpy
and then the command afterwards. I put in in a path and when I write cal.py in the command line:
/usr/bin/cal.py: line 5: print: command not found
I don't want to issue cal.py to run my script, I want it to be issued with calpy
I'm running Arch Linux if that helps, thanks. Sorry for my English.
In order for bash to know to run your script via the Python interpreter, you need to put an appropriate shebang at the start. For example:
#!/usr/bin/python
tells bash to run /usr/bin/python with your script as the first argument. I personally prefer
#!/usr/bin/env python
which is compatible with virtualenv. You also need to ensure that the permissions on your script allow it to be executed:
~$ chmod +x path/to/cal.py
Finally, in order to call cal rather than path/to/cal.py, you need to remove the .py extension and make sure that the directory containing cal is in your command search path. I prefer to add ~/bin to the search path by modifying the $PATH environment variable in ~/.bashrc:
export PATH=$HOME/bin:$PATH
then put my own executables in ~/bin. You could also copy (or symlink) cal to one of the system-wide binary directories (/bin or /usr/bin), but I consider it bad practice to mess with system-wide directories unnecessarily.
Ok, you need a couple of things for achive what you want.
First you have to tell your script "How" is going to execute/interpret it. You can do this writting
#/usr/bin/env python
at the very beggining of the file.
The problem you have is the system is trying to execute the script using bash. And in bash there is no print command.
Second you need give execution privileges to your script. And of course if you want to call your script through the command "calcpy", the script has to be called like that.
pacman first.)Put this (exactly this) as the first line of your script:
#!/usr/bin/env python
