I have an array:
list[0]=.abc.com
list[1]=.dd.eu
list[3]=.ww.bb.com
list[4]=.abc.bgs.eu
i want to remove all items from array that ends with ".com"
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3 Answers
You can do:
s='.com'
echo "${list[@]/*$s/}"
.dd.eu .abc.bgs.eu
Or else to store resulting array in a new array:
s='.com'
read -ra arr <<< "${list[@]/*$s/}"
declare -p arr
declare -a arr='([0]=".dd.eu" [1]=".abc.bgs.eu")'
5 Comments
Kriss
this looks nice and fast : echo "${list[@]/*.com/}" but i need to pass variable to it. The ".com" part must be variable - how to do it ? echo "${list[@]/"$var"/}" does not work
anubhava
sure that can be done, see updated answer.
anubhava
declare -p arr is for printing the array content resulting from read call. What I've shown above is output of declare -p arr
Tom Fenech
Does this approach work when there are spaces in the element strings?
anubhava
Would need some tweaking but here OP is dealing with some domain names so space shouldn't be there IMO.
Simple approach - make a new array containing the elements you're interested in keeping:
new_list=()
for i in "${list[@]}"; do [[ $i != *.com ]] && new_list+=( "$i" ); done
Comments
You can try this:
This stores array results in a different array.
declare -a pattern=( ${list[@]/*.com/} )
echo ${pattern[@]}
Here list is your array
list[0]=.abc.com
list[1]=.dd.eu
list[3]=.ww.bb.com
list[4]=.abc.bgs.eu
and pattern is the resulting array with the following output:
.dd.eu .abc.bgs.eu
