Confused with output while working with Strings

Question

    String sb1 = new String("Soft");
    String sb2 = new String("Soft");

    System.out.println("ANS1->" +sb1 == sb2);
    System.out.println(sb1 == sb2 + " After result");
    System.out.println("ANS2->" +sb1.equals(sb2));

This leads to output as below, but i dont understand why "ANS1" and "After result" texts are not displayed. Kindly help on this.

false

ANS2->true

try to use equals instead of == as u used in your third output — Zorian
– Zorian, Commented Mar 26, 2015 at 11:45

TheLostMind · Accepted Answer · 2015-03-26 12:42:32Z

5

Because : "ANS1->" +sb1 == sb2 ==> ("ANS1->" +sb1) == sb2. Now, the compiler does this and prints false because ("ANS1->" +sb1) !=sb2.

Even : System.out.println("ANS1->" +sb1 == sb1); prints false :P

edited Mar 26, 2015 at 12:42

answered Mar 26, 2015 at 11:42

TheLostMind

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1 Comment

Shetty's Over a year ago

Thanks lot.. :) Correct way to code is "System.out.println("ANS1->" +(sb1== sb2));"

Christian St. · Accepted Answer · 2015-03-26 12:08:49Z

1

In addition to TheLostMinds´ answer:

System.out.println("ANS1->" + (sb1 == sb2));
System.out.println((sb1 == sb2) + " After result");

Now you see the "lost" strings.

answered Mar 26, 2015 at 12:08

Christian St.

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