Compare two arrays get unique values javascript

Question

So I have an object array called Banker and i have an array called remove_banker_id,

so in my code remove_banker_id = [11, 99]. My banker object banker.id has 11 and 99 and i dont want to include them in my third array so how do i do tht?

My current code has this in my javascript file

   $.each(data, function( index, banker ) {
      $.each(lender_banker_id_array, function(index, banker_id) {
        if(parseInt(banker_id) !== banker.id) {
           banker_object
             .append($('<option>', {value: banker.id, html: banker.name }))
             .removeAttr('disabled');
         }
      })
   });

So basically if any lender_banker_id_array is in banker object, do not append it. But with this code it is not working properly. How do i solve this

Nathan · Accepted Answer · 2015-03-27 04:49:09Z

1

Try using the jquery utility function $.inArray()

http://api.jquery.com/jquery.inarray/

It returns the index of a value in an array. It returns -1 if the array does not contain the value.

$.each(data, function( index, banker ) {
    if($.inArray(banker.id, lender_banker_id_array) == -1) {
        banker_object.append($('<option>', {
           value: banker.id, 
           html: banker.name 
        })).removeAttr('disabled');
    }
});

answered Mar 27, 2015 at 4:49

Nathan

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3 Comments

Kingsley Simon Over a year ago

neat, sweet answer @nathan. thnks bruv

Downgoat Over a year ago

I highly recommend using Array.prototype.indexOf() it's faster and also is just better to use a native function against a non native.

Nathan Over a year ago

@vihan1086 it probably is faster, but it's not supported in IE < 9. So if you want to have broad browser support you'll have to use a polyfill or something and at some point the trade off isn't worth the extra millisecond.

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