Comparing a string in a string object using java

Question

I'm having a config entry, from which I'm loading into an String array like

String s = "abc$#def$#ghi";
String[] scbHLNewArray = s.split("\\$\\#");

Here I'm comparing a string with the array values after splitting it like ,

for(String arrNewErrorInfo : scbHLNewArray) {
   LOG.info("SCB HL New Error Value :"+arrNewErrorInfo+"\n");
   if(errorInfo.equals(arrNewErrorInfo)) {
       LOG.info("SCB HL Matched New value is :"+arrNewErrorInfo);
       newState = ApplicationState.NEW;
       addApplicationEvent(application.getId(),comment, ApplicationEventType.COMMENT,BBConstants.AUTOBOT);
       scbHLNewStatus = "Matched";
       break;
       }
}

I want to use some util classes like List.. Any idea on append to list and compare the string with the list objecT?

Thanks, Nizam

I really don't see what your question is, sorry. You append to a list via add. And you can ask if a String is inside your list with contains... What exactly is your question? — Florian Schaetz
– Florian Schaetz, Commented Mar 30, 2015 at 10:05
@FlorianSchaetz, My question is instead of assigning it to an Array, can we assign it to a list and compare some string with the list — Syed
– Syed, Commented Mar 30, 2015 at 10:06

Pratik · Accepted Answer · 2015-03-30 10:10:34Z

1

you can do this with List contains method.

ArrayList<Integer> arrlist = new ArrayList<Integer<(8);

  // use add() method to add elements in the list
  arrlist.add(20);
  arrlist.add(25);
  arrlist.add(10);
  arrlist.add(15);        


  // list contains element 10
  boolean retval = arrlist.contains(10); // It will return true.

answered Mar 30, 2015 at 10:10

Pratik

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Comments

Florian Schaetz · Accepted Answer · 2015-03-30 10:16:25Z

0

Ok, let's try... First of all, you can create a List Object, wrapping your array very easily:

List<String> myList = Arrays.asList( scbHLNewArray );

Be carefull, because you can NOT add to this list, as it only wraps your array. If you want a list you can add to, you would have to create a new one, for example:

List<String> myModifiableList = new ArrayList<String>( myList );

This will create a new List that contains all the Strings from the first one but is also modifiable (you can add Strings, if you want).

In any case, you can use "contains", as Pratik has already shown, to test if a String is inside your list:

if (myList.contains("someString")) { ... }

This works because the String class already has well implemented equals(...) and hashCode() methods. If you want to put other Object than Strings into your list, you would have to make sure that these methods are implemented well, otherwise contains might not work as expected.

answered Mar 30, 2015 at 10:16

Florian Schaetz

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3 Comments

Syed Over a year ago

Cool explanation Florian. I'm doing in this way.. Please check it .. String errorInfo = bankBridgeServiceResponse.getResponseString(); List<String> listSCBHLNewErrMsgs= new ArrayList<String>(Arrays.asList(SCBHL_NEW_ERRORMESSAGES.split("\\$\\#"))); boolean newErrMsgStatus = listSCBHLNewErrMsgs.contains(errorInfo);

Florian Schaetz Over a year ago

Sounds about right, except you don't need the ArrayList, the one returned by Arrays.asList should suffice as long as you only want to know if the String is inside the original array. And, as a personal note: I would not combine many operations into one line (like you are doing with new ArrayList, asList and split), it makes the code harder to read and doesn't really improve performance.

Syed Over a year ago

My question is.. I don't want an array.. then convert it into list object.

cнŝdk · Accepted Answer · 2015-03-30 10:37:07Z

0

Yes you can use a list of course, you need to :

1. Take the result of split as an array.

2. Then convert this array to a list.

String s = "abc$#def$#ghi";
String[] scbHLNewArray = s.split("\\$\\#");
List<String> list=Arrays.asList(scbHLNewArray); //convert the array to a list

Take a look at Arrays.asList(Array a) and this Tutorial for further information about it.

And then to search the wanted String object you can use indexOf(Object o) or contains(Object o) List methods

edited Mar 30, 2015 at 10:37

answered Mar 30, 2015 at 10:24

cнŝdk

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