jquery if variable in a list of values

Question

I have some jquery checking the choice made in a drop down.

function toggleFields() {
if ($("#chosenmove1").val() == 4)
    $("#hideme").show();
else
    $("#hideme").hide();
}

This works fine but I would like to change it so it checks a list of values like

if ($("#chosenmove1").val() in (3,4,5))

How can I write this to make it work (the above doesn't)

Tried a bit more

var arr = [3,4,5];
var value = $("#chosenmove1").val();
alert(value);

if ($.inArray(value, arr) > -1)
    $("#hideme").show();
else
    $("#hideme").hide();

}

The alert box tells me var value is getting the right value from the drop down - yet the show hide wont work under this setup. IF I replace var value = $("#chosenmove1").val(); with var value = 3; then it does work?

looks like that's what i mean - i want to check if the user has clicked on the drop down with the corresponding value of either 3,4 or 5 — user1479891
– user1479891, Commented Mar 30, 2015 at 12:22
possible duplicate of Jquery, checking if a value exists in array or not — Chris Baker
– Chris Baker, Commented Mar 30, 2015 at 14:48

user1479891 · Accepted Answer · 2015-03-30 13:07:33Z

5

Below is my working code: the array numbers needed to be in quotes?

function toggleFields() {
var arr = ['3','4','5'];
var value = $("#chosenmove1").val();

if (jQuery.inArray(value, arr) > -1)
    $("#hideme").show();
else
    $("#hideme").hide();

}

answered Mar 30, 2015 at 13:07

user1479891

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1 Comment

Bing Over a year ago

This answer is actually better if you're using strings. arr.indexOf does not seem to play nice with strings in @Richard Macarthy's answer.

rxjmx · Accepted Answer · 2015-03-30 12:23:10Z

0

You can use indexOf

var arr=[1,2,3];

if(!arr.indexOf(1)){ // Your value here
    alert("exists");
}

https://jsfiddle.net/xkcd8vko/1/

answered Mar 30, 2015 at 12:23

rxjmx

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