Php - in_array() and ! in_array() check 0 value

Question

if(( (in_array(0,$status_arr)) || (in_array(0,$genstatus_arr)) ) && 
    ((!in_array(0,$escalation_arr)) || (!in_array(0,$genescalation_arr))) ){

     echo 'Something';

}else if(( (in_array(1,$status_arr)) || (in_array(1,$genstatus_arr)) )){

    echo 'Something Else';

}

Here I am comparing 0 value in_array and non-zero which is !in_array. The results varies according to if-else condition but does not output expected result.

To avoid this, I tried with the third parameter, true, placing the comparison in strict mode which will not only compare values, but types as well:

How can I check if 0 or 1 exists in some array and do not exist in another array ?

The array values would be like below:

var_dump($status_arr);
   array (size=6)
  0 => string '0' (length=1)
  1 => string '0' (length=1)
  2 => string '0' (length=1)
  3 => string '0' (length=1)
  4 => string '0' (length=1)

var_dump($genstatus_arr);
   array (size=6)
  0 => string '1' (length=1)
  1 => string '1' (length=1)
  2 => string '1' (length=1)
  3 => string '1' (length=1)
  4 => string '1' (length=1)

For the below condition its not working

if( (in_array(0,$status_arr)) && (!in_array(0,$genstatus_arr)) )

Also its not a possible duplicate of IN ARRAY

"Results are abnormal" – what results do you get and what do you expect instead? — deceze
– deceze ♦, Commented Apr 3, 2015 at 7:05
the edit that you made is for which array? can you be more specific? — Adrian Cid Almaguer
– Adrian Cid Almaguer, Commented Apr 3, 2015 at 7:06
Abnormal here states, that if I expect in_array to check value 0 inside an array is not working. Also !in_array — Slimshadddyyy
– Slimshadddyyy, Commented Apr 3, 2015 at 7:06

Hanky Panky · Accepted Answer · 2015-04-03 07:13:51Z

0

var_dump(in_array(0, $status_arr, true));

Should return true, nothing abnormal there. If you are seeing false it is most probably because either of your 0's is a string 0 and not numeric 0.

If that is the case, remove the strict parameter

$array=array(0,2,3);
var_dump(in_array(0,$array,true));

Returns

 bool(true)

And

$array=array('0','2','3');
var_dump(in_array(0,$array,true));

Returns

bool(false)

You mentioned

For the below condition its not working

print_r($status_arr);
Array([0] => 0 [1] => 0 [2] => 0 [3] => 0 [4] => 0 [5] => 0)

print_r($genstatus_arr);
Array([0] => 1 [1] => 1 [2] => 1 [3] => 1 [4] => 1 [5] => 1)

if( (in_array(0,$status_arr)) && (!in_array(0,$genstatus_arr)) )

Which is an incorrect observation, because the condition works perfectly fine.

Example

answered Apr 3, 2015 at 7:13

Hanky Panky

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3 Comments

Slimshadddyyy Over a year ago

var_dump(in_array(0, $genstatus_arr, true)); outputs boolean false. Should I make it in_array('0')

Hanky Panky Over a year ago

Why do you want that last true parameter in there? Just remove it. That will match a 0 with a 0 but not a 0 with a '0' Since one is a number and other is a string.

Hanky Panky Over a year ago

var_dump(in_array(0, $genstatus_arr));

Adrian Cid Almaguer · Accepted Answer · 2015-04-03 07:23:51Z

In your case your are trying to work with strings

var_dump($status_arr);
   array (size=6)
  0 => string '0' (length=1)
  1 => string '0' (length=1)
  2 => string '0' (length=1)
  3 => string '0' (length=1)
  4 => string '0' (length=1)

var_dump($genstatus_arr);
   array (size=6)
  0 => string '1' (length=1)
  1 => string '1' (length=1)
  2 => string '1' (length=1)
  3 => string '1' (length=1)
  4 => string '1' (length=1)

Just try this example:

<?php

$status_arr = array();
$status_arr = array_pad($status_arr, 6, 0);

$genstatus_arr = array();
$genstatus_arr = array_pad($genstatus_arr, 6, 1);

var_dump($status_arr);
var_dump($genstatus_arr);

if( (in_array(0,$status_arr)) && (!in_array(0,$genstatus_arr)) )  {

     echo 'Works as espected';

}

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