PHP array(Undefined offset)

Question

here's something that confuse me, the code is the same but this got this undefined offset, and here's the code :

<?php
$day = array("Sunday"    => "Minggu",
               "Monday"    => "Senin",
               "Tuesday"   => "Selasa",
               "Wednesday" => "Rabu",
               "Thursday"  => "Kamis",
               "Friday"    => "Jumat",
               "Saturday"  => "Sabtu");
$elemen = date(1);
echo("Today is : $day[$elemen]");

?>

the code is the same on my friend but mine show this undefined offset, but him show Today is bla bla without any error. looking forward for the hint. thanks i really appreciate it..

No response from peoples asking question, even after asking. frustrating. deleting my answer — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Mar 24, 2016 at 19:50

Mureinik · Accepted Answer · 2015-04-06 06:12:48Z

1

date accepts a format string, which 1 isn't. I'm guessing you tried to use the format to retrieve today's name, which would be 'l' (a lower case L):

$elemen = date('l');

edited Apr 6, 2015 at 6:12

answered Apr 6, 2015 at 6:07

Mureinik

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2 Comments

Death-is-the-real-truth Over a year ago

It again gives:-Notice: Use of undefined constant l - assumed 'l' in your php file path on line 9 Today is : Senin

Mureinik Over a year ago

@anantkumarsingh got caught up explaining the formatting I completely forgot about quoting the 'l'. Fixed, see my edited answer.

Marcello B. · Accepted Answer · 2019-09-18 19:06:26Z

0

Try

(!empty($day[sunday]))

This check would possibly solve your problem

edited Sep 18, 2019 at 19:06

Marcello B.

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answered Sep 17, 2019 at 23:33

Brad Bal

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