Nested list remove duplicate list

Question

In a nested list (like the one below) that is continuous, I want to remove duplicate entry where first and third are equal values. What is the most efficient way of doing this?

 [[a, 1, a], [b, 1, b], [c, 2, d],[e, 4,g]

Return

 [[c, 2, d],[e, 4,g]]

Said more clearly you want to return all sublists which are not like [x, y, x]. Is that correct? — mins
– mins, Commented Apr 9, 2015 at 17:33

Kevin · Accepted Answer · 2015-04-09 17:29:43Z

2

>>> seq = [['a', 1, 'a'], ['b', 1, 'b'], ['c', 2, 'd'],['e', 4, 'g']]
>>> seq = [item for item in seq if item[0] != item[2]]
>>> print seq
[['c', 2, 'd'], ['e', 4, 'g']]

answered Apr 9, 2015 at 17:29

Kevin

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Comments

heinst · Accepted Answer · 2015-04-09 17:33:51Z

1

What you want to do is go through each sublist, and go through each item in that sublist. I there is a duplicate item in that sublist set the flag to True and ignore it, if not then append that list to a new list.

lists = [['a', 1, 'a'], ['b', 1, 'b'], ['c', 2, 'd'],['e', 4,'g']]
newLists = []
for l in lists:
    if l[0] != l[len(l) - 1]:
        newLists.append(l)

print newLists

edited Apr 9, 2015 at 17:33

answered Apr 9, 2015 at 17:27

heinst

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1 Comment

Kevin Over a year ago

This looks like it would incorrectly eliminate some values. For example, ['e', 'e','g'] would be removed even though its first item doesn't equal its third item.

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